4n-8
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The corresponding equation, is solve n when :- 2(n - 4) = -8 2n - 8 = -8 2n = -8 + 8 = 0 n = 0
It is 3*abs(n - 6) + 4*n
8-n
n-8
Yes. By definition a multiple of 8 is any number that can be expressed as 8*n, where n is an integer. But 8n=4*(2*n), and 2*n is an integer, when n is an integer. Because 8n equals four times an integer, 8n is a multiple of 4.