X/4=13 4x/4=13*4 x=13*4 x=52
1 x 52, 2 x 26, 4 x 13, 13 x 4, 26 x 2, 52 x 1
1 x 52, 2 x 26, 4 x 13, 13 x 4, 26 x 2, 52 x 1.
13 x 0 = 0 13 x 1 = 13 13 x 2 = 26 13 x 3 = 39 13 x 4 = 52 13 x 5 = 65 13 x 6 = 78 13 x 7 = 91 13 x 8 = 104 13 x 9 = 117 13 x 10 = 130 13 x 11 = 143 13 x 12 = 156 13 x 13 = 169
1404. 4 = 22 26 = 2 x 13 351 = 33 x 13 lcm = 22 x 33 x 13 = 1404
X/4=13 4x/4=13*4 x=13*4 x=52
1 x 52, 2 x 26, 4 x 13, 13 x 4, 26 x 2, 52 x 1
x - 7 - 4 = 13 (-7 - 4 = -13) x - 11 = 13 add 11 to both sides x = 24
X - 4 = 9 add 4 to each side X = 13 check 13 - 4 = 9 9 = 9
x=9; y=4; x=x+y; #x=13;y=4; y=x-y; #y=13-4=9; x=x-y; #x=13-9=4;
-9-2x+x = -13 -2x+x = -13+9 -x = -4 x = 4
If you mean x+4 = 13 then the value of x is 9
1) x+9=13 (subtract 9) x=4 2) x+9=13 (divide by 9) x/9+1=13/9 (use Pascals theorem of 1) (x+4)/2=4 x+4=8 x=4
13 > -10 + x/4 if 23 > x/4 if 92 > x that is, when x < 92
[ (x - 4) / 15 ] / [(2x + 13) / 15] = (x - 4) / (2x + 13)
Just substitute 4 in for X. 13 - 2(4) 13 - 8 = 5 ===
4 x 13 = 52