3p+7 = 16+2p 3p-2p = 16-7 p = 9
3p = 2p + 12 subtract 2p from both sides 3p - 2p = 2p - 2p + 12 1p = 12 p = 12 this is how you solve this problem.
It equals 2p because p+p=2p.
If: 2p+5r = q Then: p = (q-5r)/2
23p.
-2p-18
3p+7 = 16+2p 3p-2p = 16-7 p = 9
3p = 2p + 12subtracting 2p from both sidesp = 12 ■
p + 22q2
3p = 2p + 12 subtract 2p from both sides 3p - 2p = 2p - 2p + 12 1p = 12 p = 12 this is how you solve this problem.
20p2 + 100p + 125 = 5(4p2 + 20p + 25) = 5(4p2 + 10p + 10p + 25) = 5(2p(2p + 5) + 5(2p + 5)) = 5(2p + 5)(2p + 5) = 5(2p + 5)2
It equals 2p because p+p=2p.
2p + 34 = 2*(p + 17)
-3+4p-2p=1 -3+2p=1 2p=4 p=2
If: 2p+5r = q Then: p = (q-5r)/2
If you mean: 7p-3p+4-2 = 2p-1+10 => 4p+2 = 2p+9 => 2p = 7 Therefore: p = 7/2 => p = 3.5
23p.