9x+6=51 9x = 45 x= 5 9x-6=51 9x = 57 x= 6.33
50 x 30 = 1500 50 x 6 = 300 30 x 1 = 30 6 x 1 = 6
x = -51 -x = 51
Let the lowest odd number equal x, thus: x + x + 2 + x + 4 = 57 3x + 6 = 57 3x = 57 - 6 3x = 51 x = 51/3 x = 17 The three numbers are therefore 17, 19 and 21.
1 x 51, 3 x 17 = 51
8.5 x 6 = 51
9x+6=51 9x = 45 x= 5 9x-6=51 9x = 57 x= 6.33
[(√9)! X (√9)!] + 9 + (√9)! = [6 X 6] + 9 + 6 = 51 Note: It can also be done with just three 9s. [(√9)! x 9] - √9 = [6 x 9] - 3 = 51
51 is half 102 because 51x2 is 102
6 x 8.5 = 51
Since 6 and 51 have the common factors of 3, we can simplify the fraction to obtain: 6 / 51 = (3 x 2) / (3 x 17) = 2 / 17
6 with 38 remaining 344 - 38 = 306 = 51 x 6
1, 2, 3, 6, 17, 34, 51, 102:1 x 102, 2 x 51, 3 x 34, 6 x 17
15 + 17 + 19 = 51 The how-to is: As the numbers are consecutive and odd, each one is 2 larger than the proevious number so x + (x+2) + (x+4) = 51 so x+x+2+x+4=51 so 3x+6=51 so 3x=51-6= 45 so x=45/3=15 so x=15, x+2=17, x+4=19
51 x 6 = 306
50 x 30 = 1500 50 x 6 = 300 30 x 1 = 30 6 x 1 = 6
5 x 6 and 3 x 17