Q: What is 60 expressed as a product of its prime factors?

Write your answer...

Submit

Still have questions?

Continue Learning about Other Math

The prime factors of 60 are 2, 2, 3 and 5

they are the prime factors of 60, they are saying that 60 is equal to 2x2x3x5.

To find the HCF of two numbers you first need to express them as the product of their prime factors: 12 = 2x2x3 60 = 2x2x3x5 The next step is to identify any common factors. In this case, both numbers have two 2s and a 3 as prime factors. Multiply these together and you get 2x2x3=12 Thus the HCF of 12 and 60 is 12.

2x2x3x5

The factors of 35 are: 1, 5, 7, and 35.The prime factors of 35 are: 5 and 7.The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, and 60.The prime factors of 60 are: 2, 3, and 5.

Related questions

The number 60 as a product of prime factors is: 2 x 3 x 5 = 30

As a product of its prime factors: 2*2*3*5 = 60

Yes - as a product of 4 prime factors to be exact 60 = 2 x 2 x 3 x 5

As a product of its prime factors: 2*2*3*5 = 60 or as 22*3*5 = 60

The prime factors of 60 are: 2, 3 and 5. So, 2 x 2 x 3 x 5 = 60.

As a product of its prime factors: 2*2*3*5 = 60

As a product of its prime factors: 2*2*3*5 = 60

As a product of its prime factors: 2*2*3*5 = 60 or as 22*3*5 = 60

That's asking for the prime factorization. Writing 60 as a product of its prime factors would be 2 x 2 x 3 x 5 = 60.

5*3*2*2

2 x 2 x 3 x 5 = 60

2 x 2 x 3 x 5 = 60