2 × 2 × 3 × 5
The prime factors of 60 are 2, 2, 3 and 5
2x2x3x5
The factors of 35 are: 1, 5, 7, and 35.The prime factors of 35 are: 5 and 7.The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, and 60.The prime factors of 60 are: 2, 3, and 5.
To do this you first need to express each number as a product of their prime factors: 36 = 2x2x3x3 60 = 2x2x3x5 The next step is to identify any common prime factors. In this case, both numbers have a 2 a 2 and a 3 as prime factors. Multiply these together and you get 12. Therefore the HCF of 36 and 60 is 12. To find the LCM, multiply the numbers together and divide by the hcf: 36x60/12 = 180 So 180 is the LCM of 36 and 60.
The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, and 60.The prime factors of 60 are: 2, 3, and 5.The factors of 135 are: 1, 3, 5, 9, 15, 27, 45, and 135.The prime factors of 135 are: 3 and 5.
As a product of its prime factors: 2*2*3*5 = 60
Yes - as a product of 4 prime factors to be exact 60 = 2 x 2 x 3 x 5
As a product of its prime factors: 2*2*3*5 = 60 or as 22*3*5 = 60
The prime factors of 60 are: 2, 3 and 5. So, 2 x 2 x 3 x 5 = 60.
As a product of its prime factors: 2*2*3*5 = 60
As a product of its prime factors: 2*2*3*5 = 60
As a product of its prime factors: 2*2*3*5 = 60 or as 22*3*5 = 60
That's asking for the prime factorization. Writing 60 as a product of its prime factors would be 2 x 2 x 3 x 5 = 60.
5*3*2*2
2 x 2 x 3 x 5 = 60
As a product of its prime factors: 2*2*3*5 = 60
2 x 2 x 3 x 5 = 60