6,618 is divisible by these numbers from 1 to 12: 1, 2, 3 and 6.
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3. 813/3 = 271. If you add up the digits 8+1+3=12. 12 is divisible by 3, therefore 813 is.
No. 560 is not evenly divisible by 12.
No. 88 is not evenly divisible by 12.
All numbers, m, of the following form are evenly divisible by 12: m = 12 * n (where n is a positive integer) Here are some numbers that are divisible by 12: 12, 24, 36, 48, 60, 72, 84, 96, 108, 120, 132, 144, 156, 168, 180, 192, 204, 216, 228, 240
7 + 4 + 1 = 12 which is divisible by 3, so 741 is divisible by 3 741 is odd, all multiples of 4 are even, 741 is not divisible by 4 (Alternatively 4 x 2 + 1 x 1 = 9 which is not divisible by 4, so 741 not divisible by 4) All multiples of 5 end with 5 or 0, 741 ends with 1, so 741 not divisible by 5 To be divisible by 6, the number must be divisible by 2 (even) and divisible by 3.741 is odd, so not divisible by 2, so 741 is not divisible by 6 7 + 4 + 1 = 12 which is not divisible by 9, so 741 is not divisible by 9 All multiples of 10 end with 0, 741 ends with 1 so 741 is not divisible by 10 Summary: 741 is divisible by 3, but not by 4, 5, 6, 9 nor 10.