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What are subsets of the set N containing the numbers 1 2 3 4 and 5?
There are 32 possible subset from the set {1, 2, 3, 4, 5}, ranging from 0 elements (the empty set) to 5 elements (the whole set): 0 elements: {} 1 element: {1}, {2}, {3}, {4}, {5} 2 elements: {1, 2}, {1, 3}, {1, 4}, {1, 5}, {2, 3}, {2, 4}, {2, 5}, {3, 4,}, {3, 5}, {4, 5} 3 elements: {1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 4}, {1, 3, 5}, {1, 4, 5}, {2, 3, 4}, {2, 3, 5}, {2, 4, 5}, {3, 4, 5} 4 elements: {1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 4, 5}, {1, 3, 4, 5}, {2, 3, 4, 5} 5 elements: {1, 2, 3, 4, 5} The number of sets in each row above is each successive column from row 5 of Pascal's triangle. This can be calculated using the nCr formula where n = 5 and r is the number of elements (r = 0, 1, ..., 5). The total number of subset is given by the sum of row 5 of Pascal's triangle which is given by the formula 2^row, which is this case is 2^5 = 32.
What is 1 and 1 over 4 subtracted by 3 over 4?
1 1/4 - 3/4 = (1×4+1)/4 - 3/4 = 5/4 - 3/4 = (5-3)/4 = 2/4 = (1×2)/(2×2) = 1/2
Why is 7 the most likely answer If you roll 2 fair dice and add the scores?
If you roll two dice, the following reuslts are possible: 2: 1+1 3: 1+2 , 2+1 4: 1+3, 2+2, 3+1 5: 1+4, 2+3, 3+2, 4+1 6: 1+5, 2+4, 3+3, 4+2, 5+1 7: 1+6, 2+5, 3+4, 4+3, 5+2, 6+1 8: 2+6, 3+5, 4+4, 5+3, 6+2 9: 3+6, 4+5, 5+4, 6+3 10: 4+6, 5+5, 6+4 11: 5+6, 6+5 12: 6+6 As you can see, the greatest number of permutations result in a total of 7. Its probability is 6/36 or 1/6.
What is the difference between -5 -1 2 5 1 -2 - 4 -4 -5 -2 -1 0 0 1?
+4 +3 +3 -4 -3 -2 0 -1 +3 +1+1 0 +1
At which place in this series would you find the first seven 1 1 1 1 1 1 2 1 1 1 3 1 2 2 2 2 3 2 2 2?
It is Mathematically impossible. In order to find a single 7 in 1 1 1 1 2 1 1 1 3 1 2 2 2 2 3 2 2 2 The order would be as a requirement: 1 1 1 1 2 1 1 1 1 3 2 2 2 2 3 2 2 2 2 4 3 3 3 3 4 3 3 3 3 5 4 4 4 4 5 4 4 4 4 6 --- --- 5 5 5 5 6 5 5 5 5 7 (THERE!) If in that order the first 7 would be the 50th number. as from that you can see that the first 14 would be the 100th number, as well as the 21 being the 150th and so on.
What is the sample space for rolling a pair of dice?
The sample space is the following set: {(1. 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2. 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3. 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4. 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5. 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6. 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
How many ways can three numbers add up to ten?
1 4 5 1 3 6 2 4 4 6 3 1 8 1 1 3 3 4 1 2 7 2 3 5 4 1 5 5 1 4 1 5 4 6 3 1 1 1 8 7 2 1 4 3 3 3 4 3 5 3 2 2 5 3 5 4 1 6 1 3 1 6 3 2 1 7 1 7 2 1 8 1 4 4 2 4 2 4 2 7 1 4 5 1
What are the possible outscomes for a six sided die?
1-1 1-2 1-3 1-4 1-5 1-6 2-1 2-2 2-3 2-4 2-5 2-6 3-1 3-2 3-3 3-4 3-5 3-6 4-1 4-2 4-3 4-4 4-5 4-6 5-1 5-2 5-3 5-4 5-4 5-6 6-1 6-2 6-3 6-4 6-5 6-6 So there ARE 36 possible outcomes, you see. Answer BY: Magda Krysnki (grade sevener) :P
What are the Answers for the Piano Plays on HorseIsle?
Who: DixieLocation: Hotton, Desert IsleKeystrokes:1, 3, 2, 4, 3, 5, 4, 6, 5, 7, 6, 8, 8, 6,7, 5, 6, 4, 5, 3, 4, 2, 3, 1, 1Who: ElainaLocation: Wington, Bird IsleKeystrokes:3, 2, 1, 2, 3, 3, 3, 2, 2, 2, 3, 5, 5, 3,2, 1, 2, 3, 3, 3, 3, 2, 2, 3, 2, 1Who: HeinrichLocation: Chillton, Snow IsleKeystrokes:5, 3, 2, 1, 2, 3, 5, 3, 2, 1, 2, 3, 5, 3,5, 6, 3, 6, 5, 3, 2, 1Who: InaraLocation: Appleton, Horse IsleKeystrokes:3, 3, 4, 5, 5, 4, 3, 2, 1, 1, 2, 3, 3, 2, 2,3, 3, 4, 5, 5, 4, 3, 2, 1, 1, 2, 3, 2, 1, 1Who: JasperLocation: Earton, Horse IsleKeystrokes:1, 2, 3, 4, 5, 6, 7, 8Who: KyleighLocation: Witherton, Rider IsleKeystrokes:3, 3, 5, 3, 2, 3, 1, 5, 5, 6, 5, 4, 5, 2, 8,7, 6, 5, 4, 3, 2, 5, 3, 2, 3, 1Who: SandraLocation: Flipperton, Dolphin IsleKeystrokes:1, 1, 2, 1, 2, 3, 2, 3, 4, 3, 4, 5, 4, 5, 6, 5,6, 7, 6, 7, 8, 5, 3, 1Who: SorenLocation: Crystalton, Ice IsleKeystrokes:3, 5, 3, 2, 1, 3, 5, 3, 2, 1, 2, 3, 4, 5,6, 5, 4, 3, 2Who: VeronicaLocation: Shellton, Turtle IsleKeystrokes:3, 2, 1, 3, 2, 1, 5, 4, 4, 3, 5, 4, 4, 3, 5, 8, 8,7, 6, 7, 8, 5, 5, 5, 8, 8, 7, 6,7 8, 5, 5, 4, 3, 2, 1Who: YancyLocation: Treeton, Horse IsleKeystrokes:1, 1, 5, 5, 6, 6, 5, 4, 4, 3, 3, 2, 2, 1, 5, 5, 4, 4, 3, 3,2, 5, 5, 4, 4, 3, 3, 2, 1, 1, 5, 5, 6, 6, 5, 4, 4, 3, 3, 2, 2, 1
What are subsets of the set N containing the numbers 1 2 3 4 and 5?
There are 32 possible subset from the set {1, 2, 3, 4, 5}, ranging from 0 elements (the empty set) to 5 elements (the whole set): 0 elements: {} 1 element: {1}, {2}, {3}, {4}, {5} 2 elements: {1, 2}, {1, 3}, {1, 4}, {1, 5}, {2, 3}, {2, 4}, {2, 5}, {3, 4,}, {3, 5}, {4, 5} 3 elements: {1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 4}, {1, 3, 5}, {1, 4, 5}, {2, 3, 4}, {2, 3, 5}, {2, 4, 5}, {3, 4, 5} 4 elements: {1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 4, 5}, {1, 3, 4, 5}, {2, 3, 4, 5} 5 elements: {1, 2, 3, 4, 5} The number of sets in each row above is each successive column from row 5 of Pascal's triangle. This can be calculated using the nCr formula where n = 5 and r is the number of elements (r = 0, 1, ..., 5). The total number of subset is given by the sum of row 5 of Pascal's triangle which is given by the formula 2^row, which is this case is 2^5 = 32.
What are the combinations of rolling 2 dice?
In a combination the order does not matter, so they are: 1 1 , 1 2 , 1 3 , 1 4 , 1 5 , 1 6 2 2 , 2 3 , 2 4 , 2 5 , 2 6 3 3 , 3 4 , 3 5 , 3 6 4 4 , 4 5 , 4 6 5 5 , 5 6 6 6
How do you Play a song for Veronica's children on horseisle?
1, 1, 5, 5, 6, 6, 5, 4, 4, 3, 3, 2, 2, 1, 5, 5, 4, 4, 3, 3, 2, 5, 5, 4, 4, 3, 3, 2, 1, 1, 5, 5, 6, 6, 5, 4, 4, 3, 3, 2, 2, 1. Play these numbers on the Piano. Also asking the person in the house will also help you.
What is the Abracadabra form of Numerology?
1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 1 2 3 4 5 6 1 2 3 4 5 1 2 3 4 1 2 3 1 2 1
How do you play Baa baa black sheep on the piano?
you play like this 1 1 5 5 6 7 1 6 5 4 4 3 3 2 2 1 5 5 5 4 4 3 3 3 2 5 5 5 4 5 6 4 3 2 2 1
If a 6 sided number cube is rolled twice how many possible outcomes are there?
6*6=36 1&1; 1&2; 1&3; 1&4; 1&5; 1&6 2&1; 2&2; 2&3; 2&4; 2&5; 2&6 3&1; 3&2; 3&3; 3&4; 3&5; 3&6 4&1; 4&2; 4&3; 4&4; 4&5; 4&6 5&1; 5&2; 5&3; 5&4; 5&5; 5&6 6&1; 6&2; 6&3; 6&4; 6&5; 6&6 For adding up roll one and roll two, the outcomes are 1+1= 2 1+2=2+1= 3 1+3=2+2=3+1= 4 1+4=2+3=3+2=4+1= 5 1+5=2+4=3+3=4+2=5+1= 6 1+6=2+5=3+4=4+3=5+2=6+1= 7 2+6=3+5=4+4=5+3=6+2= 8 3+6=4+5=5+4=6+3= 9 4+6=5+5=6+4= 10 5+6=6+5= 11 6+6= 12 Odds of adding up to those possible outcomes. 2 = 1:36 3 = 2:36 = 1:18 4 = 3:36 = 1:12 5 = 4:36 = 1:9 6 = 5:36 7 = 6:36 = 1:6 You will total seven more times than others. 8 = 5:36 9 = 4:36 = 1:9 10= 3:36 = 1:12 11= 2:36 = 1:18 12= 1:36
What is 1 and 1 over 4 subtracted by 3 over 4?
1 1/4 - 3/4 = (1×4+1)/4 - 3/4 = 5/4 - 3/4 = (5-3)/4 = 2/4 = (1×2)/(2×2) = 1/2
How do you beat bubble blast 2 pack 2 level 12?
5-1 5-1 2-1 4-5 or 4-5 2-1 5-1 5-1
