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It is 120.

You seem to be unaware of the fact that you could have obtained the answer much more easily and quickly by using the calculator that comes as part of your computer.

Q: What is 6 x 5 x 4 x 3 x 2 x 1?

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There are 32 possible subset from the set {1, 2, 3, 4, 5}, ranging from 0 elements (the empty set) to 5 elements (the whole set): 0 elements: {} 1 element: {1}, {2}, {3}, {4}, {5} 2 elements: {1, 2}, {1, 3}, {1, 4}, {1, 5}, {2, 3}, {2, 4}, {2, 5}, {3, 4,}, {3, 5}, {4, 5} 3 elements: {1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 4}, {1, 3, 5}, {1, 4, 5}, {2, 3, 4}, {2, 3, 5}, {2, 4, 5}, {3, 4, 5} 4 elements: {1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 4, 5}, {1, 3, 4, 5}, {2, 3, 4, 5} 5 elements: {1, 2, 3, 4, 5} The number of sets in each row above is each successive column from row 5 of Pascal's triangle. This can be calculated using the nCr formula where n = 5 and r is the number of elements (r = 0, 1, ..., 5). The total number of subset is given by the sum of row 5 of Pascal's triangle which is given by the formula 2^row, which is this case is 2^5 = 32.

1 1/4 - 3/4 = (1×4+1)/4 - 3/4 = 5/4 - 3/4 = (5-3)/4 = 2/4 = (1×2)/(2×2) = 1/2

If you roll two dice, the following reuslts are possible: 2: 1+1 3: 1+2 , 2+1 4: 1+3, 2+2, 3+1 5: 1+4, 2+3, 3+2, 4+1 6: 1+5, 2+4, 3+3, 4+2, 5+1 7: 1+6, 2+5, 3+4, 4+3, 5+2, 6+1 8: 2+6, 3+5, 4+4, 5+3, 6+2 9: 3+6, 4+5, 5+4, 6+3 10: 4+6, 5+5, 6+4 11: 5+6, 6+5 12: 6+6 As you can see, the greatest number of permutations result in a total of 7. Its probability is 6/36 or 1/6.

+4 +3 +3 -4 -3 -2 0 -1 +3 +1+1 0 +1

It is Mathematically impossible. In order to find a single 7 in 1 1 1 1 2 1 1 1 3 1 2 2 2 2 3 2 2 2 The order would be as a requirement: 1 1 1 1 2 1 1 1 1 3 2 2 2 2 3 2 2 2 2 4 3 3 3 3 4 3 3 3 3 5 4 4 4 4 5 4 4 4 4 6 --- --- 5 5 5 5 6 5 5 5 5 7 (THERE!) If in that order the first 7 would be the 50th number. as from that you can see that the first 14 would be the 100th number, as well as the 21 being the 150th and so on.

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There are 64 subsets, and they are:{}, {A}, {1}, {2}, {3}, {4}, {5}, {A,1}, {A,2}, {A,3}, {A,4}, {A,5}, {1,2}, {1,3}, {1,4}, {1,5}, {2,3}, {2,4}, {2,5}, {3,4}, {3, 5}, {4,5}, {A, 1, 2}, {A, 1, 3}, {A, 1, 4}, {A, 1, 5}, {A, 2, 3}, {A, 2, 4}, {A, 2, 5}, {A, 3, 4}, {A, 3, 5}, {A, 4, 5}, {1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 4}, {1, 3, 5}, {1, 4, 5}, {2, 3, 4}, {2, 3, 5}, {2, 4, 5}, {3, 4, 5}, {A, 1, 2, 3}, {A, 1, 2, 4}, {A, 1, 2, 5}, {A, 1, 3, 4}, {A, 1, 3, 5}, {A, 1, 4, 5}, {A, 2, 3, 4}, {A, 2, 3, 5}, {A, 2, 4, 5}, {A, 3, 4, 5}, {1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 4, 5}, {1, 3, 4, 5}, {2, 3, 4, 5}, {A, 1, 2, 3, 4}, {A, 1, 2, 3, 5}, {A, 1, 2, 4, 5}, {A, 1, 3, 4, 5}, {A, 2, 3, 4, 5}, {1, 2, 3, 4, 5} {A, 1, 2, 3,,4, 5} .

The sample space is the following set: {(1. 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2. 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3. 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4. 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5. 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6. 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

1 4 5 1 3 6 2 4 4 6 3 1 8 1 1 3 3 4 1 2 7 2 3 5 4 1 5 5 1 4 1 5 4 6 3 1 1 1 8 7 2 1 4 3 3 3 4 3 5 3 2 2 5 3 5 4 1 6 1 3 1 6 3 2 1 7 1 7 2 1 8 1 4 4 2 4 2 4 2 7 1 4 5 1

2 and 275/300 which simplifies to 2 11/12, or 2.916666..... this is possible as ((6*1)+(9*2)+(8*3)+(8*4)+(5*5))/(36).

1-1 1-2 1-3 1-4 1-5 1-6 2-1 2-2 2-3 2-4 2-5 2-6 3-1 3-2 3-3 3-4 3-5 3-6 4-1 4-2 4-3 4-4 4-5 4-6 5-1 5-2 5-3 5-4 5-4 5-6 6-1 6-2 6-3 6-4 6-5 6-6 So there ARE 36 possible outcomes, you see. Answer BY: Magda Krysnki (grade sevener) :P

Who: DixieLocation: Hotton, Desert IsleKeystrokes:1, 3, 2, 4, 3, 5, 4, 6, 5, 7, 6, 8, 8, 6,7, 5, 6, 4, 5, 3, 4, 2, 3, 1, 1Who: ElainaLocation: Wington, Bird IsleKeystrokes:3, 2, 1, 2, 3, 3, 3, 2, 2, 2, 3, 5, 5, 3,2, 1, 2, 3, 3, 3, 3, 2, 2, 3, 2, 1Who: HeinrichLocation: Chillton, Snow IsleKeystrokes:5, 3, 2, 1, 2, 3, 5, 3, 2, 1, 2, 3, 5, 3,5, 6, 3, 6, 5, 3, 2, 1Who: InaraLocation: Appleton, Horse IsleKeystrokes:3, 3, 4, 5, 5, 4, 3, 2, 1, 1, 2, 3, 3, 2, 2,3, 3, 4, 5, 5, 4, 3, 2, 1, 1, 2, 3, 2, 1, 1Who: JasperLocation: Earton, Horse IsleKeystrokes:1, 2, 3, 4, 5, 6, 7, 8Who: KyleighLocation: Witherton, Rider IsleKeystrokes:3, 3, 5, 3, 2, 3, 1, 5, 5, 6, 5, 4, 5, 2, 8,7, 6, 5, 4, 3, 2, 5, 3, 2, 3, 1Who: SandraLocation: Flipperton, Dolphin IsleKeystrokes:1, 1, 2, 1, 2, 3, 2, 3, 4, 3, 4, 5, 4, 5, 6, 5,6, 7, 6, 7, 8, 5, 3, 1Who: SorenLocation: Crystalton, Ice IsleKeystrokes:3, 5, 3, 2, 1, 3, 5, 3, 2, 1, 2, 3, 4, 5,6, 5, 4, 3, 2Who: VeronicaLocation: Shellton, Turtle IsleKeystrokes:3, 2, 1, 3, 2, 1, 5, 4, 4, 3, 5, 4, 4, 3, 5, 8, 8,7, 6, 7, 8, 5, 5, 5, 8, 8, 7, 6,7 8, 5, 5, 4, 3, 2, 1Who: YancyLocation: Treeton, Horse IsleKeystrokes:1, 1, 5, 5, 6, 6, 5, 4, 4, 3, 3, 2, 2, 1, 5, 5, 4, 4, 3, 3,2, 5, 5, 4, 4, 3, 3, 2, 1, 1, 5, 5, 6, 6, 5, 4, 4, 3, 3, 2, 2, 1

There are 32 possible subset from the set {1, 2, 3, 4, 5}, ranging from 0 elements (the empty set) to 5 elements (the whole set): 0 elements: {} 1 element: {1}, {2}, {3}, {4}, {5} 2 elements: {1, 2}, {1, 3}, {1, 4}, {1, 5}, {2, 3}, {2, 4}, {2, 5}, {3, 4,}, {3, 5}, {4, 5} 3 elements: {1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 4}, {1, 3, 5}, {1, 4, 5}, {2, 3, 4}, {2, 3, 5}, {2, 4, 5}, {3, 4, 5} 4 elements: {1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 4, 5}, {1, 3, 4, 5}, {2, 3, 4, 5} 5 elements: {1, 2, 3, 4, 5} The number of sets in each row above is each successive column from row 5 of Pascal's triangle. This can be calculated using the nCr formula where n = 5 and r is the number of elements (r = 0, 1, ..., 5). The total number of subset is given by the sum of row 5 of Pascal's triangle which is given by the formula 2^row, which is this case is 2^5 = 32.

2/4, 3/6, 4/8, 5/10,... To get the equivalent fractions of 1/2: Multiply 1/2 by 2/2, 3/3, 4/4, 5/5,... 1/2 * 2/2 = 2/4 1/2 * 3/3 = 3/6 1/2 * 4/4 = 4/8 1/2 * 5/5 = 5/10

In a combination the order does not matter, so they are: 1 1 , 1 2 , 1 3 , 1 4 , 1 5 , 1 6 2 2 , 2 3 , 2 4 , 2 5 , 2 6 3 3 , 3 4 , 3 5 , 3 6 4 4 , 4 5 , 4 6 5 5 , 5 6 6 6

1, 1, 5, 5, 6, 6, 5, 4, 4, 3, 3, 2, 2, 1, 5, 5, 4, 4, 3, 3, 2, 5, 5, 4, 4, 3, 3, 2, 1, 1, 5, 5, 6, 6, 5, 4, 4, 3, 3, 2, 2, 1. Play these numbers on the Piano. Also asking the person in the house will also help you.

3-4, 3-5, 3-3, 1-3 or 3-4, 3-5, 2-2, 5-3 or 2-2, 3-4, 3-5, 5-3

1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 1 2 3 4 5 6 1 2 3 4 5 1 2 3 4 1 2 3 1 2 1