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Assuming you mean 0.81818181...repeating; the answer is 9/11.

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βˆ™ 13y ago
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βˆ™ 9y ago

9 / 11

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Q: What is 81 repeating as a fraction?
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Related questions

What is 0.81 repeating in fraction?

It is: 81/99


What is 0.81 repeating as a fraction?

n= .81 repeating 100n = 81.81 -1n -1n 99n= 81 81/99 81 over 99 is the final answer.


What is .81 repeating decimal as a fraction?

9/11


How do you write 0.81 repeating as a fraction in simplest form?

Oh, dude, you just take the repeating decimal 0.81 and turn it into a fraction. It's like a piece of cake! So, 0.81 repeating is 81/99, and when you simplify that fraction, you get 9/11. Easy peasy, lemon squeezy!


What is 0.194 as a repeating fraction?

what is 0.194 as a repeating fraction


What is 0.78 repeating as a fraction?

0.78 repeating as a fraction = 78/99


What is 1.4 repeating as a fraction?

0.14 repeating as a fraction = 14/99


What is 81 percent as a fraction?

Fraction: 81/100 Decimal: 0.81


What is 0.15 repeating as a fraction?

If you mean: 0.151515.....repeating then as a fraction it is 5/33


What is 3.1 repeating into a fraction?

Well, isn't that just a happy little number! 3.1 repeating is the same as 3.1 with a line over the 1, which means it goes on forever. To turn it into a fraction, we can write it as 31/9, because the repeating 1 means we're dividing by 9. Just like painting a beautiful landscape, turning decimals into fractions is all about finding the right brushstrokes!


What is 1.49 ( 4 and 9 repeating) in a fraction?

What is 1.49 repeating (9 is repeating)


What is 53.3 repeating in fraction form?

In fraction form, 53.3 repeating can be expressed as 533/9. To convert a decimal with a repeating decimal point to a fraction, we first determine the non-repeating part of the decimal (in this case, 53), then subtract it from the entire decimal to isolate the repeating part (0.3 repeating). Next, we express the repeating part as a fraction over 9 (since there is one digit repeating). Thus, 53.3 repeating is equal to 533/9 in fraction form.