All multiples of 890, which is an infinite number, including 890, 1780, 2670, 3560, 4450 . . .
No. The factors of 6 are 2 and 3, so in order for a number to be divisible by 6, it must be divisible by 3 and divisible by 2. This can be checked without actually doing the division.890 is divisible by 2, since the last digit is either {0,2,4,6 or 8} (zero in this case)To check for divisibility by 3, add the digits and if the sum is divisible by 3, then the number is divisible by 3: 8 + 9 + 0 = 17. If you don't know if this sum is divisible by 3, then you can just keep adding until you get a single digit number: 1 + 7 = 8.The only single digit numbers which are divisible by 3 are {3, 6 & 9 }So 890 is not divisible by 3, therefore it is not divisible by 6. The whole process can be done in a few seconds in your head, with practice.
90% of 890= 90% * 890= 0.9 * 890= 801
Here are some even numbers that are divisible by 5: 10 20 30 40 50 100 600 720 890 1110 2340 3360 108,070 224,560 Any number that is divisible by 10 (which means it ends in "0") is also divisible by 5.
880
7,120 is evenly divisible by these numbers: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80, 89, 178, 356, 445, 712, 890, 1424, 1780, 3560 and 7120.
12 x 890 = 10680 12% x 890 = 106.8
53.4 is 6% of 890. 890 + 53.4 = 943.4
It is 1000-110 = 890
12% of 890 is 106.8 Method: (12 × 890) ÷ 100 = 106.8
894 to the nearest 10 = 890
There are 89 tens in 890.