890 is evenly divisible by these numbers: 1 2 5 10 89 178 445 and 890.
All multiples of 890, which is an infinite number, including 890, 1780, 2670, 3560, 4450 . . .
No. The factors of 6 are 2 and 3, so in order for a number to be divisible by 6, it must be divisible by 3 and divisible by 2. This can be checked without actually doing the division.890 is divisible by 2, since the last digit is either {0,2,4,6 or 8} (zero in this case)To check for divisibility by 3, add the digits and if the sum is divisible by 3, then the number is divisible by 3: 8 + 9 + 0 = 17. If you don't know if this sum is divisible by 3, then you can just keep adding until you get a single digit number: 1 + 7 = 8.The only single digit numbers which are divisible by 3 are {3, 6 & 9 }So 890 is not divisible by 3, therefore it is not divisible by 6. The whole process can be done in a few seconds in your head, with practice.
Here are some even numbers that are divisible by 5: 10 20 30 40 50 100 600 720 890 1110 2340 3360 108,070 224,560 Any number that is divisible by 10 (which means it ends in "0") is also divisible by 5.
90% of 890= 90% * 890= 0.9 * 890= 801
7,120 is evenly divisible by these numbers: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80, 89, 178, 356, 445, 712, 890, 1424, 1780, 3560 and 7120.
890
53.4 is 6% of 890. 890 + 53.4 = 943.4
It is 1000-110 = 890
12 x 890 = 10680 12% x 890 = 106.8
12% of 890 is 106.8 Method: (12 × 890) ÷ 100 = 106.8
894 to the nearest 10 = 890
890