83 + 6*7*9 + 1 = 512 + 378 + 1 = 891
6x2+5x+1 = (3x+1)(2x+1) when factored
999 and 1
14
1st term is 1 to the power of 1 = 1 2nd term is 2 to the power of 2 = 4 3rd term is 3 to the power of 3 = 27 4th term is 4 to the power of 4 = 256
1
Infinity.
(x + 4)(x2 - x - 1)
(x + 4)(x2 - x - 1)
(x + 4)(x2 - x - 1)
Assuming this is your original formula: -3p3+ 5p + -2p2 + -4 - -12p + 5 - -8p3You combine like terms, where the p exponent is the same, to produce:5p3 - 2p2 + 17p + 1
Factor it. y(4y - 1)(3y - 2) = 0 y = 0, 1/4, 2/3
7a minus 2, if "3a-2" means 3a minus 2. 3a plus 1 and 1-3rd in parenthesis times 3a, if "3a-2" means 3a squared. a plus 3a squared plus 3a = 1-3rd times 3a plus 3a times 3a plus 1 times 3a = 3a plus 1 and 1-3rd in parenthesis times 3a
10 ( x = -3)
3³ + 1³ = 27 + 1 = 28
The question is ambiguous: xa+1 * xa+1 = x2(a+1) or (xa + 1)(xa + 1) = x2a + 2xa + 1
3n+2 + (3n+3 - 3n+1) = 3n+1+1 + (3n+1+2 - 3n+1) = 3*3n+1 + (9*3n+1 - 3n+1)= (3+9-1)*3n+1 = 11*3n+1.
the answer is 10 and 3 6th