(a^2 + 8b)(a^2 - 5b)
Two equations, two unknownsFirst, multiply 3a + 2b = 70 by 4. This gives the equation 12a + 8b = 96. Next, subtract 4a + 8b = 70 from this equation. This result gives 8a = 26, which, solving for a, gives a = 3.25.Substitue the value of a into one of the original equations, which will give b = 7.125.Finally check your results by substituting the values of a and b into each equation.Answer:Given two equations 3a + 2b = 24 ------ (1) and 4a + 8b = 70 ------ (2) We have to solve this by using elimination method.Multiply the equation 3a + 2b = 24 by 4 on both the sides.We get 12a + 8b = 96 ---------- (3)Now, subtract the equation (2) from equation (3)12a + 8b = 96 ---------- (3)4a + 8b = 70 ---------- (2)--------------------------------(12a - 4a) + (8b - 8b) = (96 - 70)8a + 0 = 268a = 26a = 26/8a = 13/4 (Or) a = 3.25Substitute the value of a in the equation (2)4a + 8b = 70 ---------- (2)4(13/4) + 8b = 70.13 + 8b = 708b = 70 - 138b = 57b = 57/8 (Or) b = 7.125
(11a + 8b)(11a - 8b)
To factorize the expression 7a^2 - 8ab, you need to find the greatest common factor of the two terms. In this case, the common factor is a. So, you can factor out an 'a' to get a(7a - 8b) as the factored form of the expression. This means that 7a^2 - 8ab can be simplified as a multiplied by the quantity (7a - 8b).
6a + (7b - 4a - 8b) = (6a - 4a) + (7b - 8b) = 2a - b
8b^2 -9b +1 8b^2 -8b -b +1 8b(b-1) - 1(b-1) (8b-1)(b-1)
(8a)(8b) = (8c)/(8d); multiply both sides by 8d to obtain (8a)(8b)(8d) = (8c); divide both sides by 8 to obtain (8a)(8b)d = c; divide both sides by (8a)(8b) to obtain d = c/[(8c)(8b)].
b^2 + 8b + 7 factors to (b + 7)(b + 1)
2(a + 4b)
(a^2 + 8b)(a^2 - 5b)
One of the factors is 3x + 8b. The other is 9x^2 -24xb + 64b^2
If you mean 8b+4b = 56-16b then the value of b works out as 2
Two equations, two unknownsFirst, multiply 3a + 2b = 70 by 4. This gives the equation 12a + 8b = 96. Next, subtract 4a + 8b = 70 from this equation. This result gives 8a = 26, which, solving for a, gives a = 3.25.Substitue the value of a into one of the original equations, which will give b = 7.125.Finally check your results by substituting the values of a and b into each equation.Answer:Given two equations 3a + 2b = 24 ------ (1) and 4a + 8b = 70 ------ (2) We have to solve this by using elimination method.Multiply the equation 3a + 2b = 24 by 4 on both the sides.We get 12a + 8b = 96 ---------- (3)Now, subtract the equation (2) from equation (3)12a + 8b = 96 ---------- (3)4a + 8b = 70 ---------- (2)--------------------------------(12a - 4a) + (8b - 8b) = (96 - 70)8a + 0 = 268a = 26a = 26/8a = 13/4 (Or) a = 3.25Substitute the value of a in the equation (2)4a + 8b = 70 ---------- (2)4(13/4) + 8b = 70.13 + 8b = 708b = 70 - 138b = 57b = 57/8 (Or) b = 7.125
-2
8b - 12c = -4
3b-8b = -5
8b + 11 - 3b = 2b + 2 5b + 11 = 2b + 2 5b - 2b = 2 - 11 3b = -9 b = -3