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If 3a plus 2b equals 24 and 4a plus 8b equals 70 how do you solve for a and b using the elimination method?
Wiki User
∙ 12y ago
Next, subtract 4a + 8b = 70 from this equation. This result gives 8a = 26, which, solving for a, gives a = 3.25.
Substitue the value of a into one of the original equations, which will give b = 7.125.
Finally check your results by substituting the values of a and b into each equation.
Answer:Given two equations 3a + 2b = 24 ------ (1) and 4a + 8b = 70 ------ (2)We have to solve this by using elimination method.
Multiply the equation 3a + 2b = 24 by 4 on both the sides.
We get 12a + 8b = 96 ---------- (3)
Now, subtract the equation (2) from equation (3)
12a + 8b = 96 ---------- (3)
4a + 8b = 70 ---------- (2)
--------------------------------
(12a - 4a) + (8b - 8b) = (96 - 70)
8a + 0 = 26
8a = 26
a = 26/8
a = 13/4 (Or) a = 3.25
Substitute the value of a in the equation (2)
4a + 8b = 70 ---------- (2)
4(13/4) + 8b = 70.
13 + 8b = 70
8b = 70 - 13
8b = 57
b = 57/8 (Or) b = 7.125
Wiki User
∙ 12y ago
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