Q: What is 8x 2 over 3?

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5x-3=2-8x 5x-3+3=2-8x+3 5x=5-8x 5x+8x=5-8x+8x 13x=5 x=5/13

-6

-4

8x^3 - 12x^2 + 6x - 9 = (8x^3 - 12x^2) + (6x - 9) = 4x^2(2x - 3) + 3(2x - 3) = (4x^2 + 3)(2x - 3)

8x - 1 = 11 8x = 12 x = 12 / 8 or x = 3 / 2.

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I assume 8x to 5th is in denominator 4x^2/8x^5 = x^2/2x^5 = 1/2x^3 = 0.5x to the negative 3

5x-3=2-8x 5x-3+3=2-8x+3 5x=5-8x 5x+8x=5-8x+8x 13x=5 x=5/13

-6

(8x + 3)2 ie (8x + 3)(8x + 3)

-4

1/4 = 3 - 2x - 1/ x + 24 ( 3 - 2x - 1 ) = 1 ( x + 2 )12 - 8x - 4 = x + 28 - 8x = x + 2-8x - x = 2 - 8-9x = -6x = -6/-9X = 2/3

Is that really the equation? 2y8x-3=0? Or should it be 2y+8x-3 or 2y-8x-3....Either way the goal is to get this equation to the y=mx+b format. m being the slope and b being where x crosses zero. Lets start (I'll use 2y-8x-3=0 for easy signs).Lets add 3 to both sides2y-8x-3+3=0+3 -> 2y-8x=3Now lets add 8x to both sides2y-8x+8x=3+8x -> 2y=8x+3Now we need to divide 2 on both sides so that y is by itself(2y/2)=(8x+3)/2 -> y=(8x+3)/2Let's simplifyy=8x/2 + 3/2 -> y=4x + 3/2Now look back at what we wanted (y=mx + b) and our equation is now in that format. Since m is the slope, the actual slope of the line will be 4

y=-2x^2+8x+3

8x^3 - 12x^2 + 6x - 9 = (8x^3 - 12x^2) + (6x - 9) = 4x^2(2x - 3) + 3(2x - 3) = (4x^2 + 3)(2x - 3)

3/2

x^2-8x+3 = x^2-8x+16-16+3 = (x-4)^2-13 y=(x-4)^2 -13 The vertex is (4,-13).

8/-3 + -7/2 = 8x-2/-3x-2 + -7x3/2x3= -16/6 + -21/6= -37/6