It cannot be proven because it is not true. Suppose S1 = {0,1,2,3} and S2 = {0,5,10} then S1 u S2 = {0,1,2,3,5,10} then |S1| = n = 4, |S2| = m = 3 but |S1 u S2| = 6 which is NOT n+m = 7
1.96
14
98
49.7551
4.9
B -1.92 m/s2
PE = m•g•h, where m is mass in kg, g is 9.8m/s2, and h is height in meters.PE = 5.0kg x 9.8m/s2 x 2.0m = 98kg•m2/s2 = 98 Joules
The "s" in m/s^2 stands for seconds, representing the unit of time in the expression for acceleration.
F=m x a a=F/m (m/s2) a=(vend-vbeginning)/(tend-tbeginning) m/s2
-1.92 m/s2
Yes acceleration equals velocity divided by time i.e a=v/t and it's S.I unit is m/s2
F = ma =>m = F/a = 12/0.4 = 30 grams
It cannot be proven because it is not true. Suppose S1 = {0,1,2,3} and S2 = {0,5,10} then S1 u S2 = {0,1,2,3,5,10} then |S1| = n = 4, |S2| = m = 3 but |S1 u S2| = 6 which is NOT n+m = 7
Force, in Newtons, can be expressed as Kg*m/s2. Acceleration can be expressed as m/s2. If you divide it out, you get:= N / (m/s2)
The acceleration of gravity on the surface of the moon is 1.623 m/s2 . (9.807 m/s2 on Earth)
F = m Am = F / 2.5The mass will be the (ionic force) divided by 2.5 m/s2 .