It cannot be proven because it is not true.
Suppose S1 = {0,1,2,3} and S2 = {0,5,10} then S1 u S2 = {0,1,2,3,5,10}
then |S1| = n = 4, |S2| = m = 3
but |S1 u S2| = 6 which is NOT n+m = 7
You can't it equals 2. You can't it equals 2.
2048
This is a very difficult philosophical question. The best way to look at it is that 2 is defined as 1 plus 1 ! (If it isn't, how do you define 2?)
If you mean 2 plus 2 equals 5 it is possible. 2 plus 2 equals 22 (or it could also be 4 if you want it but must be 22 to make 5...it makes sense) V is the 22nd letter in the alphabet and the roman numeral for V is 5. BOOM! 2 PLUS 2 EQUALS 5!
4+1=5. Plus 4 equals 9. Plus 77685769844446473 equals 77685769844446482. Plus 3 equals 77685769844446485. Plus 8 equals 77685769844446493. Plus 1 equals 77685769844446494. Plus 9870998342523322424 equals 1064785604097768918. Plus 4 equals 1064785604097768922.
You can't it equals 2. You can't it equals 2.
No you can not prove that 9 +10 = 21.
Using a calculator
Because there is no way to define the divisors, the equations cannot be evaluated.
2 plus 2 eqauls 4 2 times 2 equals 4
Sinθ plus cosθ2 plus sinθ-cosθ2 equals 2 does not equal 2. It equals 2sinθ. The cosθ2 terms cancel out and you are left with sinθ + sinθ which is 2sinθ.
Yes
This is called the Abel-Ruffini theorem.
No, because technically, it is not true.
This would be a real bear to prove, mainly because it's not true.
Until an "equals" sign shows up somewhere in the expression, there's nothing to prove.
It is asking you to prove that you are a human, not a macro or bot trying to spam them with messages. Just do that math, and enter the number. In this case, the answer is 19.