9.9x9.8x9.7=941.094
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The number of times that 2 can go into 99 evenly is determined by dividing 99 by 2. This division results in 49 with a remainder of 1. Therefore, 2 can go into 99 a total of 49 times with a remainder of 1.
There are infinitely many sets: For example, -99, -98, -97, ... -2, -1, 0, 1, 2, ... 97, 98, 99, 100 or 1, 1, 1, 1 ... [100 times] or 0.0001, 0.0001, 0.0001, ... [ a million times].
97 x 98 = 9506
The median is (98+99)/2 = 98.5
Assuming that everyone kisses everyone else only one time each, the first person has to kiss all 99 others. The second one only has to kiss the remaining 98, the third the remaning 97 and so on, so you'd have to add 99+98+97+96+95... etc. You can add the opposing numbers up to 100 each (99+1, 98+2, 97+3, 96+4) and count how many 100 result. The final number of kisses would then be 4950.