97 x 98 = 9506
sqrt(9506) = 97.50 So 97 and 98 are the two numbers.
27 and 28
The numbers are 14, 15, 16 and 17.
The factor pairs of 1295 are (1295,1)(259,5)(185,7)(37,35) None of them are consecutive. 35 and 37 are consecutive odd numbers.
27*28 = 756
To find two consecutive numbers with a product of 9506, we can set the numbers as ( n ) and ( n + 1 ). The equation becomes ( n(n + 1) = 9506 ). Solving for ( n ), we can approximate ( n^2 \approx 9506 ), leading to ( n \approx 97.5 ). The consecutive integers are 97 and 98, as ( 97 \times 98 = 9506 ).
sqrt(9506) = 97.50 So 97 and 98 are the two numbers.
Find two consecutive numbers with the value of 4160
28 and 29
24,25,26
27 and 28
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
15 and 13
The numbers are 14, 15, 16 and 17.
11 and 12
The factor pairs of 1295 are (1295,1)(259,5)(185,7)(37,35) None of them are consecutive. 35 and 37 are consecutive odd numbers.
27*28 = 756