9x8x7x6x5x4x3x2x1 = 362880
9x8x7x6x5x4x3x2x1 or 9! which equals 362880 possible combinations if no digits are repeated
You can solve this by doing 9!-(!-means factorial) 9!=9x8x7x6x5x4x3x2x1 So the answer is 362,880 different ways.
The number of combinations of the letters TELEPHONE is 9 factorial, or 362,880. From that, however, we have to divide by 4 to account for the E being repeated twice, so the number of distinct combinations is 90,720.
this is a combination question. Assuming the letters cannot be used again and all letters make words of the same length you do the following: There are 9 letters so: it is 9x8x7x6x5x4x3x2x1 = 362,800. Because it has 2 of the same letter (a), I think you should take away from this 8x7x6x5x4x3x2x1, i.e. take away 40,320. So I think the answer is 322480. I am not sure if this is right, but the methodology of the first part (i.e. no repeating letters) is correct