At least B and 1. There may be others depending on the value of B.
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If 'A' is 'divisible by 'B', it means that: -- If 'B' is repeatedly subtracted from 'A', then the last one fits exactly, without anything left over -- 'A' was made by piling up some whole number of 'B's, with no extras -- 'B' goes into 'A' evenly --'A'/'B'= some whole number
71 and 182
d, v, s, b, l
B
"There is a simple rule how to determine if a number is divisible by three.Add up the digits and see if the sum of those digits (a much smaller number) is divisible by three.This rule simplifies finding out if a big number is divisible by three, by reducing it to a small number.Why is this proposition true?Consider, for simplicity, a 3 digit number 'abc", such as 321.Suppose that a+b+c is divisible by 3.Our number, written as 'abc' is actually100a+10b+c.For instance, 321 = 100*3+10*2+1.Let's rewrite 100a+10b+c as 99a+a + 9b+b + c.99a+a + 9b+b + c = (99a + 9b) + (a + b + c)The first part is always divisible by 3 since numbers with all nines are always divisible by 3 (9 = 3*3, 99=33*3, 999=333*3 etc).That the second part (a+b+c) is divisible by 3, is a given.So, we have a sum of two parts, both of which are divisible by 3. This sum is, therefore, also divisible by three. Theorem proven."~http://www.algebra.com/algebra/homework/divisibility/lessons/divisibility-by-3-three.lesson~