If 'A' is 'divisible by 'B', it means that: -- If 'B' is repeatedly subtracted from 'A', then the last one fits exactly, without anything left over -- 'A' was made by piling up some whole number of 'B's, with no extras -- 'B' goes into 'A' evenly --'A'/'B'= some whole number
71 and 182
d, v, s, b, l
B
"There is a simple rule how to determine if a number is divisible by three.Add up the digits and see if the sum of those digits (a much smaller number) is divisible by three.This rule simplifies finding out if a big number is divisible by three, by reducing it to a small number.Why is this proposition true?Consider, for simplicity, a 3 digit number 'abc", such as 321.Suppose that a+b+c is divisible by 3.Our number, written as 'abc' is actually100a+10b+c.For instance, 321 = 100*3+10*2+1.Let's rewrite 100a+10b+c as 99a+a + 9b+b + c.99a+a + 9b+b + c = (99a + 9b) + (a + b + c)The first part is always divisible by 3 since numbers with all nines are always divisible by 3 (9 = 3*3, 99=33*3, 999=333*3 etc).That the second part (a+b+c) is divisible by 3, is a given.So, we have a sum of two parts, both of which are divisible by 3. This sum is, therefore, also divisible by three. Theorem proven."~http://www.algebra.com/algebra/homework/divisibility/lessons/divisibility-by-3-three.lesson~
That a = ±b
312 is divisible by 2 b/c the 2 at the end of 312 is an even number312 is divisible by 3 b/c 3 + 1 + 2 = 6 which is divisible by 3312 is divisible by 4 b/c 12 is divisible by 4312 is not divisible by 5 b/c the one's place isn't 0 or 5312 is divisible by 6 b/c 312 is divisible by 2 and 3312 is not divisible by 7 b/c 2*7=14, 31-14=17 which is not divisible by 7312 is divisible by 8 b/c 312/8=39 (Explanation: A way to find out how 8 is divisible its that its first three digits [the ones, tens, and hundreds place] have to be divisible by 8)312 is not divisible by 9 b/c 3 + 1 + 2 = 6 which is not divisible by 9312 is not divisible by 10 b/c the ones place is not 0
To be divisible by 36 the number must be divisible by 9 (and 4). To be divisible by 9, the sum of the digits must be divisible by 9. 5 + 5 = 10 → need an extra 8 → A + B = 8.
Remark: For any two numbers a and b, b never divides a exactly if b is greater than a.So, 2 is not divisible by 7623.
It means that 'b' can go evenly into 'a'
GCF of a and b is a if b is divisible by a.87 is divisible by 29 so, GCF(29,87) = 29.
Let A, B, C are digits. Number ABC is divisible by eleven if and only if A+C-B=0 or A+C-B=11
If a is divisible by b, then LCM of a and b is a.Here 12 is divisible by 2. So, LCM of 2 and 12 is 12.
No.A number a is divisible by another number b, if and only if the fraction a/b is equivalent to a whole number. And as you know, 1/2 = 0.5, which is not a whole number, hence is 1 not divisible by 2.The only number 1 is divisible by, is 1 itself. All numbers are divisible by 1.
only 324 is divisible by 4
If 'A' is 'divisible by 'B', it means that: -- If 'B' is repeatedly subtracted from 'A', then the last one fits exactly, without anything left over -- 'A' was made by piling up some whole number of 'B's, with no extras -- 'B' goes into 'A' evenly --'A'/'B'= some whole number
71 and 182