If you mean as in a right angle triangle then using Pythagoras' theorem the 3rd side is 60
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a - b = c -(a - b) = -c b - a = -c
2a. (a, b and c are all equal.)
A.
A=B , A-B=B-B , A-B =0 B=C , B-B=C-B, 0=C-B So A-B=0 but also C-B=0 A-B=C-B ...add +b ...A-B+B=C-B+B , A=C
Yes.