k/2 -k/5 -k/6 = 2 Multply all terms by 30: 15k -6k -5k = 60 4k = 60 k = 15
6 divided by the sum of 4 times x and 5 times k is equal to 6 times the reciprocal of (4x + 5k).
5.75
k - 5
10-k=5
k/2 -k/5 -k/6 = 2 Multply all terms by 30: 15k -6k -5k = 60 4k = 60 k = 15
7
K divided by 21 divided by N is equivalent to divided by?
6 divided by the sum of 4 times x and 5 times k is equal to 6 times the reciprocal of (4x + 5k).
Any one of the infinite set of numbers of the form 7 + 30*k where k is an integer.
5.75
Every number is divisible by any non-zero number.Any element of the set of numbers of the form 354*k where k is an integer is evenly divisible.
its k itself
If x ≡ 39 mod 357 then: x = 357k + 39 for some integer k. Now 357 = 21×17, and 39 = 2×17+5 → x = 21×17×k + 2×17 + 5 → x = 17(21k + 2) + 5 → x = 17m + 5 where m = 21k + 2 (is an integer) → x ≡ 5 mod 17 → the remainder when the number is divided by 17 is 5.
0.1562
65
If you mean: kk-5 then it can be k^2-5 But if you mean: k+k-5 then it can be 2k-5