it goes from +1 to 0
Na+ and Cl- are spectator ions.
let 1+2+4+8+...... =s s= 1+2(1+2+4+8+........) s=1+2s s=-1 but sum of infinite terms cannot be -1 so, what's the answer
Na+-K+ ATPase
it does not change -apex
Not sure what L(s) is supposed to be, but regardless, the oxidation state of Na changes from 1+ in NaOH to zero in Na(s).
no 2Na (s) + MgF2 ? 2NaF (s) + Mg (s) is balanced apex
it goes from +1 to 0
Lithium atom become the cation Li+.
No, it should be:2 Na(s) + 2HCl(g) --> H2(g) + 2 NaCl(s)By the way: sodium at normal conditions is a solid metal (s), not gaseous (g)
If you mean a reaction of AgNO3 + Na(s) ==> NaNO3 + Ag(s), there would be ONE electron transferred.Ag^+ + 1e- ==> Ag(s) Reduction reaction Na(s) ==> Na^+ + 1e- Oxidation reaction
s = -70
Na+ and Cl- are spectator ions.
2HCl + Na(2)S-----> H(2)S + 2NaCl
Sodium (Na) plus sulfur (S) creates sodium sulfide (Na2S). The reason is that Na gives up it's valence electron and S takes it. It takes 2 sodiums because S need TWO electrons to complete the octet. This forms the ionic compound sodium sulfide.
4,1,2
8 over 8 plus 8. Eight eighths plus 8