give the expansion of Taylor series
General answer: Math Specific Answer: Taylor Series
please let us know exactly what you want expanded, it is not clear from your question.
The first-order Taylor expansion around x2 is given by sqrt(x2 + a) ~ x + a / 2xSo for sqrt(98), we know the closes perfect square is 81 = 9^2. Therefore: sqrt(98) = sqrt(81 + 17) = sqrt(9^2 + 17) ~ 9 + 17/(2*9) = 9 + 17/18 ~ 9.9444Alternatively, sqrt(98) = sqrt(100 - 2) = sqrt(10^2 - 2) ~ 10 - 2/(2*10) = 10 - 1/10 = 9.9Using a calculator: sqrt(98) ~ 9.899Taylor series will always be an over-approximation.
14.3333
who discovered in arithmetic series
Simply because the Maclaurin series is defined to be a Taylor series where a = 0.
the Taylor series of sinx
No but Taylor Lautner is. Taylor Lautner is dating Taylor Swift.
Taylor is still in Eclipse.
The numerical value of pi is often found using a Taylor or Maclaurin series (Taylor series centered at 0).
The Taylor series was named after the mathematician Brook Taylor, who introduced it in the 18th century. The Taylor series is significant in mathematics because it allows functions to be approximated by polynomials, making complex calculations more manageable and providing insights into the behavior of functions near a specific point.
A Taylor series use to create an estimate of what a function looks like. Someone would use a Taylos series in calculus, computer science, and higher level mathematics.
Jacob ( Taylor Launter)
it was the twilight series
f(x)=lnx
Taylor Dooley and Sharkboy was Taylor Lautner. Taylor Lautner is also Jacob Black in the Twilight Series
the answer is kent Taylor