Well 99.99999(repeating) = 100
The rigorous proof for this involves expressing 99.9999...9 as a geometric series and then calculating the number to which is converges, which is exactly 100. Interesting huh? Or you can think about it like this: Since there is no number you can chose that is between 99.9999(repeating) and 100, which is impossible for two different numbers, they must be equal.
This also applies here: 9.9999(repeating) = 10
So 99.99(repeating) + 9.99(repeating) = 110.
However 9 repeating = Infinity.
Therefor your answer is simply infinity, as infinity is not a number so you can not get Infinity + 110.
99.9 repeating plus 9.9 repeating plus 9 repeating = infinity
2,106.9
1.0 × 10^56
0.16 repeating = 16/99.
nothing
The answer is 6.99574217 × 1013
999 + 99 = 1098
0.0991
999 trillion plus 99 million is 999,000,099,000,000
2,106.9
Notice the pattern. 0.7 repeating = 7/9 0.57 repeating - 57/99 0.357 repeating = 357/999
Depending upon which digit(s) is/are repeating:0.23555... = (2.355... - 0.235...)/9 = 2.12/9 = 212/900 = 53/2250.2353535... = (23.535... - 0.235...)/99 = 23.3/99 = 233/9900.235235235... = 235/999
Find the repeating bit. i.e. In 0.45454545 the repeating bit is 45 If it has 2 digits divide it by 99, if it has three digits divide by 999 and so on So with 0.45454545, we divide 45 by 99 Cancell down this fraction to get the final answer 45/99=5/11 so 0.45454545 = 45/99= 5/11
The LCM of 99 and 999 is 10989
99 999 999 980 000 000 001
Yes. Put the repeating digits over the same number of 9s and simplify. eg 0.18181818... = 18/99 = 2/11 eg 0.123123... = 123/999 = 41/333
1.0 × 10^56
0.16 repeating = 16/99.