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How do you factor y2 plus 8y plus 16?
y2 + 8y + 16 = y2 + 4y + 4y + 16 = y(y + 4) + 4(y + 4) = (y + 4)(y + 4) or (y + 4)2
What is 66-3y plus y2 from 88 plus 5y-y2?
88 + 5y - y2 66 - 3y + y2 Subtract: 22 + 8y -2y2
Find the center and radius of the circle given by the equation x2 plus y2-10x plus 8y plus 5 equals 0?
The standard equation of a circle with center C(h,k) and radius r is as follows:(x - h)2 + (y - k)2 = r2(x2 -2hx +h2) + (y2 - 2ky + k2)We have...x2 + y2 - 10x + 8y + 5 =0x2 - 10x + y2 + 8y + 5 =0add h2 and k2 to both sides(x2 - 10x + h2) + (y2 + 8y + k2) = -5 + h2 + k2Using the above framework we can see that 10 = 2h, h = 5Using the above framework we can see that 8 = 2k, k = 4So the formula is(x2 - 10x + 25) + (y2 + 8y + 16) = -5 + 25 + 16(x - 5)2 + (y - 4)2 = 36the center of the circle is C(5,4) and radius 6
Find the radius of a circle with the equation x2 plus y2 equals 16?
x2 +y2 = R2 =16 = radius 2 R = 4
The equation of a circle centered at the origin is x2 plus y2 16. What is the radius of the circle?
If that equals 16 then the radius is 4
How do you factor y2 plus 8y plus 16?
y2 + 8y + 16 = y2 + 4y + 4y + 16 = y(y + 4) + 4(y + 4) = (y + 4)(y + 4) or (y + 4)2
What is the answer to y2 plus 8y plus 7?
If you mean y2+8y+7=0 then it is a quadratic. y2+8y+7+9-9=0 y2+8y+16-9=0 (y+4)2=9 y+4=3 , y+4=-3 y=-1 , y=-7 So y can equal -1 or -7.
What is the perimeter of the curve x2 plus y2-12x-8y-43 equals 0?
Let's first reformat it: x2 + y2 - 12x - 8y - 43 = 0 x2 - 12x + 36 + y2 - 8y + 16 = 43 + 36 + 16 (x - 6)2 + (y - 4)2 = 95 So this equation defines a circle, with a center point at (6, 4) and a perimeter (i.e. circumference) of √95.
What is 66-3y plus y2 from 88 plus 5y-y2?
88 + 5y - y2 66 - 3y + y2 Subtract: 22 + 8y -2y2
Find the center and radius of the circle given by the equation x2 plus y2-10x plus 8y plus 5 equals 0?
The standard equation of a circle with center C(h,k) and radius r is as follows:(x - h)2 + (y - k)2 = r2(x2 -2hx +h2) + (y2 - 2ky + k2)We have...x2 + y2 - 10x + 8y + 5 =0x2 - 10x + y2 + 8y + 5 =0add h2 and k2 to both sides(x2 - 10x + h2) + (y2 + 8y + k2) = -5 + h2 + k2Using the above framework we can see that 10 = 2h, h = 5Using the above framework we can see that 8 = 2k, k = 4So the formula is(x2 - 10x + 25) + (y2 + 8y + 16) = -5 + 25 + 16(x - 5)2 + (y - 4)2 = 36the center of the circle is C(5,4) and radius 6
X2 plus y2 equals 16 radius of the circle?
4
What is the solution to x2 plus 2y-6x plus 8y-1 equals x2-y2 plus 4x-6y-1?
x2 + 2y - 6x + 8y - 1 = x2 - y2 + 4x + 6y - 1 y2 - 10x + 4y = 0 y(y+4) = 10x It cannot be solved completely because with two variables (x and y) you need two independent equations for a full solution.
Find the radius of a circle with the equation x2 plus y2 equals 16?
x2 +y2 = R2 =16 = radius 2 R = 4
Factor y2-8y plus 15?
It goes to (x-5)(x-3)
What is the radius for a circle whose equation is x2 plus y2 16?
I think you have missed out an equals sign. If you mean x2 + y2 = 16, then the radius is 4.
The equation of a circle centered at the origin is x2 plus y2 16. What is the radius of the circle?
If that equals 16 then the radius is 4
How do you find the radius of a circle with a defined equation of x2 plus y2-12x plus 8y plus 43 equals 0?
First, complete the square: x^2 - 12x + __ and y^2 + 8y + __.so we have x^2 - 12x + 36 = (x - 6)^2, and y^2 + 8y + 16 = (y + 4)^2.36 + 16 = 52, so we need to add 9 to both sides [43 + 9 = 52].so the equation is now: (x - 6)2 + (y + 4)2= 9 = 3 2, so the radius is 3.
