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If a2 plus b2 equals c2 then c2 equals b2 equals?
a2
What is the reciprocal of a plus bi if a2 plus b2 equals 1?
The reciprocal of a + bi is a - bi:1/(a + bi) since the conjugate is a - bi:= 1(a - bi)/[(a + bi)(a - bi)]= (a - bi)/[a2 - (b2)(i2)] since i2 equals to -1:= (a - bi)/(a2 + b2) since a2 + b2 = 1:= a - bi/1= a - bi
What is the answer for b2 plus 16b plus 64?
b2 + 16b + 64 can be factorized to (b+8)(b+8). If they were equal to zero as in b2 + 16b + 64=0 then b = -8.
Can you simplify the square root of a2 plus b2?
Cannot be simplified
A2 plus b2 equals c2 is an example of?
Pythagorean Theorem
What are the lengths of and A plus B in a right triangle if C equals 8?
A2 + B2 = C2 If C=8, then A2 + B2 = 64
How do you calucate a2 plus b2?
a2+2a2b+2ab2+b2
If a2 plus b2 equals c2 then c2 equals b2 equals?
a2
Factor A2 plus 4a plus 4 - b2?
a2 - 4a + 4
Is a squared plus b squared the same as a plus b squared?
No. If you expand (a + b)2 you get a2 + 2ab + b2. This is not equal to a2 + b2
Why is the Pythagorean therm a2 plus b2 equals c2 not a plus b equals c?
l a2 b2 is c2!!Its completely norma
How do you simplify the square root of a squared plus b squared?
sqrt(a2 + b2) can't be simplified. Neither can (a2 + b2) .
What is the reciprocal of a plus bi if a2 plus b2 equals 1?
The reciprocal of a + bi is a - bi:1/(a + bi) since the conjugate is a - bi:= 1(a - bi)/[(a + bi)(a - bi)]= (a - bi)/[a2 - (b2)(i2)] since i2 equals to -1:= (a - bi)/(a2 + b2) since a2 + b2 = 1:= a - bi/1= a - bi
How do you factor y2-64?
y2 - 64 can be written as y2 - 82, which is of the form of a2 - b2.And a2 - b2 is factored as (a-b)(a+b).Therefore, y2 - 64 is factored as (y+8)(y-8).
How do you factor x squared-64?
x2 - 64 can be written as x2 - 82, which is of the form of a2 - b2.And a2 - b2 is factored as (a-b)(a+b).Therefore, x2 - 64 is factored as (x+8)(x-8).
How do you solve a to the 3rd power plus b to the 3rd power divided by a plus b?
(a3 + b3)/(a + b) = (a + b)*(a2 - ab + b2)/(a + b) = (a2 - ab + b2)
What is the answer for b2 plus 16b plus 64?
b2 + 16b + 64 can be factorized to (b+8)(b+8). If they were equal to zero as in b2 + 16b + 64=0 then b = -8.
