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No, a 2 by 4 rectangle is not congruent to a 4 by 8 rectangle. They are similar, but the 4 by 8 rectangle is 4 times bigger than the 2 by 4.
Yes. Say there are two rectangles, both with perimeter of 20. One of the rectangles is a 2 by 8 rectangle. The area of this rectangle is 2 x 8 which is 16. The other rectangle is a 4 by 6 rectangle. It has an area of 4 x 6 which is 24.
Length = 4, Width = 2
Area of a rectangle= length x height.For example:A 2' by 4' rectangle would have an area of 2 x 4 = 8 square feet.As a formula, it is L*W=A.
A=l*w A=8*4 A=32 diagonal cuts the rectangle into two congruent triangles. 32/2 = 16