If all the sides are equal to 5 cm, then it's a equilateral triangle.
An equilateral triangle is a triangle in which all the sides are equal.
To find the perimeter of a triangle, you simply add the lengths of all three sides together. In this case, the perimeter would be 15 cm + 17 cm + 10 cm = 42 cm. So, the perimeter of the triangle with sides measuring 15 cm, 17 cm, and 10 cm is 42 cm.
The 1st is a right angle triangle and the 2nd is a scalene triangle.
a equilateral triangle has 3 sides that each equal 15 cm
a scalene triangle is a triangle with three differant sides
There is no triangle with sides 14 cm, 3cm and 8cm. For a triangle to exist the sum of the two shorter sides must be longer than the remaining side. 3 cm + 8 cm = 11 cm < 14cm
That would be an equilateral triangle.
This is not an equilateral triangle.
Is this a trick question? Each side of the second triangle is bigger than the corresponding side in the first triangle. So the second triangle is larger.
yes
It is a scalene triangle with 3 sides of different lengths
It is an equilateral triangle
Yes. It would be an equilateral triangle with three equal sides. It would also be equiangular, with three equal angles, each measuring 60 degrees.
No because the sum of its smaller sides must be greater than its longest side
No because its longest side does not comply with Pythagoras' theorem.
A shape with a perimeter of 24 cm could be a rectangle with sides measuring 6 cm and 6 cm, a square with sides measuring 6 cm, or a triangle with sides measuring 8 cm, 8 cm, and 8 cm. These shapes all have different configurations but share the common attribute of having a total perimeter of 24 cm.
Draw a triangle with sides of 4*234 cm, 5*234 cm and 7*234 cm = 936 cm, 1170 cm and 1638 cm.
its called a scalene triangle, scalene triangles have 3 different sides to work out area you do base x Perpendicular height divided by 2 the problem is i dont know which side is base of which is hight, to work out the area of a triangle. you have given little information which is not helpful