408 is the ans
Answer: 2A number is divisible by 3 if the sum of its digits is a multiple of 3.Now 2+1+4=7. If we add 2 more it is 9 which is a multiple of 3.So 216 is divisible by 3 since 2+1+6=9 which is a multiple of 3.
To find the least number that must be added to 37969 to make it exactly divisible by 65, first, we calculate the remainder when 37969 is divided by 65. The remainder is 44 (since 37969 ÷ 65 = 584 with a remainder of 44). To make it divisible by 65, we need to add (65 - 44 = 21). Thus, the least number that must be added is 21.
To find the number that can be added to 368 to make it divisible by 27, you need to first determine the remainder when 368 is divided by 27. You can do this by finding the modulus of 368 divided by 27, which is 17. To make 368 divisible by 27, you need to add the difference between 27 and the remainder (27 - 17 = 10). Therefore, you would need to add 10 to 368 to make it divisible by 27.
It is 8961 - W*int(8961/W)
339 + 1 = 340,which is exactly divisible.
Seven
What number must be added to to make it equal to 190312
6 (or 0)
6. To check for divisibility by 9, add the digits of the number together and if the sum is divisible by 9, then the original number is divisible by 9. If the test is repeated on the sum(s) until a single digit remains, then this is the remainder when the original number is divided by 9. Subtracting this remainder from 9 will give the smallest number that needs to be added to to the original number to make it divisible by 9. For 75: 7 + 5 = 12 1 + 2 = 3 so 75 ÷ 9 has a remainder of 3, therefore add 9 - 3 = 6 to 75 to make it divisible by 9. (75 + 6 = 81 = 9 x 9).
403÷8 gives 50 as quotient and 3 as remainder. Dividend- remainder=divisor ×quotient 403-3=8*50 which is 400. our value is 403 So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.
408 is the ans
Answer: 2A number is divisible by 3 if the sum of its digits is a multiple of 3.Now 2+1+4=7. If we add 2 more it is 9 which is a multiple of 3.So 216 is divisible by 3 since 2+1+6=9 which is a multiple of 3.
Well, darling, the smallest number you can take from 4979 to make it divisible by 47 is 6. Why? Because when you subtract 6 from 4979, you get 4973, which is divisible by 47. Simple math, honey, nothing to stress about.
To find the smallest sum of money that can be added to 2.45 to make it exactly divisible by 9, we first need to determine the remainder when 2.45 is divided by 9. 2.45 can be written as 245/100. When 245 is divided by 9, the remainder is 8. To make 2.45 exactly divisible by 9, we need to add the difference between 9 and the remainder, which is 9 - 8 = 1. Therefore, the smallest sum of money that can be added to 2.45 to make it exactly divisible by 9 is $0.01.
To find the least number that must be added to 37969 to make it exactly divisible by 65, first, we calculate the remainder when 37969 is divided by 65. The remainder is 44 (since 37969 ÷ 65 = 584 with a remainder of 44). To make it divisible by 65, we need to add (65 - 44 = 21). Thus, the least number that must be added is 21.
To find the number that can be added to 368 to make it divisible by 27, you need to first determine the remainder when 368 is divided by 27. You can do this by finding the modulus of 368 divided by 27, which is 17. To make 368 divisible by 27, you need to add the difference between 27 and the remainder (27 - 17 = 10). Therefore, you would need to add 10 to 368 to make it divisible by 27.