6+n
The algebraic expression for "twice a number" would be 2x, where x represents the unknown number. To find the quotient of 2x and 6, you would divide 2x by 6, which simplifies to (2x) / 6. This can be further simplified to x / 3, which represents the final quotient of twice a number and 6 in algebraic expression.
6+3*n
6*n+25
6
v + 6
Let the original number be y Therefore the new number is given by the expression 2y + 6
n/6 + 3
6+n
n/6
An algebraic expression for "6 less than 5 and a number" is (5 - x - 6), where x represents the unknown number.
You cannot write an algebraic expression for that, you need an equation. The equation is n - 6 = 4
The algebraic expression for "twice a number" would be 2x, where x represents the unknown number. To find the quotient of 2x and 6, you would divide 2x by 6, which simplifies to (2x) / 6. This can be further simplified to x / 3, which represents the final quotient of twice a number and 6 in algebraic expression.
(6+n) n= a number
Oh, dude, it's like this - when you divide 6 by a number in algebra, you just write it as 6 divided by x, where x is the mysterious number you're dividing by. So, the algebraic expression for 6 divided by a number is 6/x. Easy peasy, right?
The algebraic expression for three more than a number is: X + 3
6/n?