6+n
6*n+25
x+6
The algebraic expression for "twice a number" would be 2x, where x represents the unknown number. To find the quotient of 2x and 6, you would divide 2x by 6, which simplifies to (2x) / 6. This can be further simplified to x / 3, which represents the final quotient of twice a number and 6 in algebraic expression.
6+3*n
6
(6+n) n= a number
You cannot write an algebraic expression for that, you need an equation. The equation is n - 6 = 4
6*n+25
It is simply: f+6
6(n + y)
(a+b)/6
x+6
n/6
6*(3+20) = 138
6
An algebraic expression for "6 less than 5 and a number" is (5 - x - 6), where x represents the unknown number.
v + 6