yes, the product of 2 odd numbers is always an odd number.
Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd.
There is a quicker way if you know how to multiply bracketed terms:
odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd.
Chat with our AI personalities
You will always get another odd number.
Yes - while multiplying odd numbers by even numbers will always produce an even result.
Let one odd number be "2m + 1", the other odd number "2n + 1" (where "m" and "n" are integers). All odd numbers have this form. If you multiply this out, you get (2m+1)(2n+1) = 4mn + 2m + 2n + 1. Since each of the first three parts is even, the "+1" at the ends converts the result into an odd number.
An odd number times an odd number is an odd number no matter which 2 odds you multiply.
If you multiply one even number by one odd number, the result is always even. In general, if you multiply several numbers, and at least one of the numbers is even, the product is always even. This is because "even" means "multiple of 2", and if one of the factors contains a 2 as a factor, so will the product.