yes, the product of 2 odd numbers is always an odd number.
Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd.
There is a quicker way if you know how to multiply bracketed terms:
odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd.
You will always get another odd number.
Yes - while multiplying odd numbers by even numbers will always produce an even result.
An odd number times an odd number is an odd number no matter which 2 odds you multiply.
Let one odd number be "2m + 1", the other odd number "2n + 1" (where "m" and "n" are integers). All odd numbers have this form. If you multiply this out, you get (2m+1)(2n+1) = 4mn + 2m + 2n + 1. Since each of the first three parts is even, the "+1" at the ends converts the result into an odd number.
If you multiply one even number by one odd number, the result is always even. In general, if you multiply several numbers, and at least one of the numbers is even, the product is always even. This is because "even" means "multiple of 2", and if one of the factors contains a 2 as a factor, so will the product.
Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd. ========================== You've just read a truly impressive answer to a question slightly different from the one that was asked. The part of the question that comes after "Why if ..." is a false statement. If you multiply odd number with another number, the result is odd number ONLY if the nother number is also odd number.
You will always get another odd number.
When you add them, you always get an even number; when you multiply them, the result is always odd.
Yes - while multiplying odd numbers by even numbers will always produce an even result.
its always an even number....im pretty sure.
I think it would be a negative answer because if you do it that many times and it is odd number it is most likely to be a negative answer than a positive answer. If you multiply a negative by another negative an even number of times, it will be even, but if it is done an odd number of times, like in your example, the result will be an odd number.
When you multiply an odd number by an even number, you are essentially adding an even number of odd numbers together. Since adding an even number of odd numbers will always result in an even number, the product will be even.
Let one odd number be "2m + 1", the other odd number "2n + 1" (where "m" and "n" are integers). All odd numbers have this form. If you multiply this out, you get (2m+1)(2n+1) = 4mn + 2m + 2n + 1. Since each of the first three parts is even, the "+1" at the ends converts the result into an odd number.
An odd number times an odd number is an odd number no matter which 2 odds you multiply.
you would get an even number; 2x1=2 2x3=6 2x5=10
Multiply 7 by any odd number, then check whether the result is between 5 and 50.
If you multiply one even number by one odd number, the result is always even. In general, if you multiply several numbers, and at least one of the numbers is even, the product is always even. This is because "even" means "multiple of 2", and if one of the factors contains a 2 as a factor, so will the product.