There is no regular polyhedron with 9 vertices There are many other defined polyhedra with 9 vertices, though:
elongated square pyramid (cube with a square pyriamd on top)
gyroelongated square pyramid
triangular cupola
triaugmented triangular prism
tridiminished icosahedron
It's hard to describe the shape of some of these. See the related links below for pictures.
A polyhedron must have at least 4 faces, at least 4 vertices and at least 6 edges.
an elongated square pyramid- here is a website with pictures(http://en.wikipedia.org/wiki/Elongated_square_pyramid )
eighthedron eighthedron
Such a polyhedron cannot exist. According to the Euler characteristics, V + F - E = 2, where V = vertices, F = faces, E = edges. This would require that the polyhedron had only two faces.
Any integer that is greater than 3.
There cannot be such a polyhedron since it does not satisfy Euler's criterion.
Triangular Prisim
It is a triangular prism that has 5 faces, 6 vertices and 9 edges
A diagonal of a polyhedron is a line between any two vertices except outer vertices.
The number of edges and vertices ina polyhedron will depend on the polyhedron one selects either to study, build or etc...
A polyhedron has 30 edges and 12 vertices. How many faces does it have
This polyhedron has 7 vertices and 12 edges.
A polyhedron must have at least 4 faces, at least 4 vertices and at least 6 edges.
It cannot be a polyhedron because it does not satisfy the Euler characteristic.
For a simply connected polyhedron,Faces + Vertices = Edges + 2
polyhedron
4