It is a line of the form y = c where c is any constant.
It is a line of the form y = c where c is any constant.
It is a line of the form y = c where c is any constant.
It is a line of the form y = c where c is any constant.
Yes, but the the line is vertical and the slope (or gradient) is undefined.
m=1/0 The m(slope) is 1/0 because it is rise over run. The line is "rising" but not "running".
because, when you go, lets say, (2,3), and the line is on the 2, you change the second number, not the 2, but the 3.The slope of a line is the ratio of rise over run. On a vertical line you have an infinite rise over zero run. Your slope would be infinity/0. As you know, you cannot divide by 0, so the slop is undefined.
Determine which line is steeper by finding out which has a greater rise over run. I trust you know what rise over run is. You can determine which has a greater rise over run by dividing the rise by the run, and then whichever line has the largest decimal is the steepest.
vertical height over lengh
The marks you're describing represent the number 1 in a prescription. The horizontal line and dot are to help prevent reading errors.
h,c
two vertical lines with a line over the top
When run = 0. That is to say, when the line is vertical.
Because slope is defined as change in y over change in x, for a vertical line your change in x is zero. Dividing by zero gives an undefined answer.
the slope of a vertical line is considered undefined slope in the rise over run. lets say the rise is 5 and the run would be 0 since its a vertical line. therefore your slope would be 5/0 and since you cannot divide by 0, the slope is undefined
Any part of the torso TOUCHING the vertical plane of the line...
When the slope is 3 over 0, it indicates a vertical line. In mathematical terms, a slope of 3 over 0 is considered undefined because division by zero is undefined in mathematics. This means that the line is vertical and does not have a defined slope in the traditional sense. The equation of a vertical line can be represented as x = a, where 'a' is the x-coordinate of any point on the line.
The dimensions, tolerances and so forth is either over a horizontal line, or to the left of a vertical.
Yes, but the the line is vertical and the slope (or gradient) is undefined.
m=1/0 The m(slope) is 1/0 because it is rise over run. The line is "rising" but not "running".
The slope of a horizontal line is zero. It has a slope, but slope = 0 and this makes it different from a vertical line which has a slope that is undefined because you cannot divide 0 over 0 which is how much a vertical line rises and runs.Ways to find slope:(y2-y1)/(x2-x1 )orrise/run