0
x = (-b (+/-) root( b2 - 4ac)) / 2a
Sorry about the messy answer, there are no square root symbols or plus-minus symbols.
Here is the proof -
ax2 + bx + c = 0 --------> multiply by 4a
4a2x2 + 4abx + 4ac = 0
4a2x2 + 4abx = -4ac ----------> add b2 to both sides
4a2x2 + 4abx + b2 = b2 - 4ac -----------> factorise LHS
(2ax + b)2 = b2 - 4ac
2ax + b = (+/-) root( b2 - 4ac)
2ax = -b (+/-) root( b2 - 4ac)
x = (-b (+/-) root( b2 - 4ac)) / 2a
Maths works people.
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∙ 12y ago
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