0
An example of an object that is 1 cm in length is a standard paperclip. Paperclips typically measure around 1 cm in length, making them a common everyday object that fits this measurement. Other examples could include a small button, a LEGO brick stud, or a standard sewing pin.
Add your answer:
Earn +20 pts
What is the length of a match stick?
1 cm
An object that measures 1 cm?
pencil eraser
Which is larger 1 mm or 1 cm?
It takes 10 mm to cover the same length as one cm, so the cm is larger.
What is 1.9 cm on a tape measure?
It is a length of 1.9 centimetres.
What is a common object that's about 1 cm in size?
A Dime!
What object is the length of a centimeter?
The length of a centimeter is approximately the width of a standard paperclip or the tip of a typical pencil.
When an object 5.0 cm tall is placed 12 cm from a converging lens an image is formed on the same side of the lens as the object but the image is 61 cm away from the lens. What is the focal length of t?
The image distance (61 cm) is positive since the image is on the same side of the lens as the object. Using the lens formula (1/f = 1/d_o + 1/d_i), where d_o is the object distance (12 cm) and d_i is the image distance, the focal length (f) of the lens is approximately 15 cm.
Concave mirror with a focal length of 10cm creates a real image 30cm away on in princial axis how far from the mirror is its coresponding object?
The mirror formula for concave mirrors is 1/f = 1/d_o + 1/d_i, where f = focal length, d_o = object distance, and d_i = image distance. Given f = 10 cm, d_i = 30 cm, we can solve for d_o: 1/10 = 1/d_o + 1/30. Solving for d_o gives d_o = 15 cm. The corresponding object is located 15 cm away from the mirror.
What is the volume of an object 28cms in length 22cm breadth and 1 cm height?
616 cubed centimeters.
What is the focal length of a converging lens which produces a virtual image four time the size of the object the image being 15 cm from the lens?
Using the lens formula (1/f = 1/do + 1/di) and the magnification formula (m = -di/do) where m = -4, you can solve for the focal length (f). Given the object distance (do = -15 cm), you can calculate the focal length to be 10 cm.
An object has a length of 20 cm a width of 5 cm a height of 1 cm and a mass of 500 g What is its density?
The volume of the object is calculated by multiplying its length, width, and height: 20 cm * 5 cm * 1 cm = 100 cm³. To find the density, divide the mass (500 g) by the volume (100 cm³): 500 g / 100 cm³ = 5 g/cm³. The density of the object is 5 g/cm³.
What is an example of a centimeter?
An ordinary fingernail (the pink part) is approx 1 cm in length.
The object distance for a convex lens is 20.0 cm and the image distance is 4.0 cm The height of the object is 10.0 cm What is the height of the image?
Using the lens formula (1/f = 1/do + 1/di), where f is the focal length, do is the object distance, and di is the image distance, we can solve for f. Once we have the focal length, we can use the magnification equation (magnification = hi/ho = -di/do) to find the height of the image where hi is the height of the image and ho is the height of the object.
How many centimeters are in a 56millimeter object?
By unit of length and distance and conversion ,we can say that 1 cm=10 mm 56 mm=5.6 cm
What is the focal length of a concave mirror that forms an image 25 cm from the mirror if the object distance is 20 cm?
1/o + 1/i = 1/ff = (o x i)/(o + i)f = 11.1 cm (rounded)
What is the formula to find the mass of a regular shaped object such as a shoe box?
length x width x height x specific weight example : 10 cm x 5 cm x 2 cm x 1 kg/cm3 = 100 kg
An object is placed in front of a converging lens in such a position that the lens f 14.0 cm creates a real image located 27.0 cm from the lens Then with the object remaining in place the lens?
If the object is kept in place while adjusting the lens, the real image will also move as the lens is adjusted. If the image moves closer to the lens, the focal length of the lens has decreased. If the image moves farther away from the lens, the focal length has increased.
