Both for logs and antilogs, the base must be specified. Once you decide on your base, you can calculate that on any scientific calculator. Use the antilog function (base 10, or base e, if that's what you need), or calculate 10 to the power -4.1 (if you want a base-10 antilog), or e to the power -4.1 (if you want a base-e antilog), or some other base to this power. In Excel, you can use the power operator. For example, for 10 to the power -4.1 (that is, the antilog, base 10), type the following in an Excel cell:
=10^-4.1
Value of AntiLog (6) is 1,000,000.00
Raise 10 to the power of the number. The antilog of 2 is 102 = 100 The antilog of 5 is 105 = 10,000 The antilog of 'pi' is 103.1416 = 1,385.46 (rounded)
56
0.008572 (rounded)
102.8 = 630.9573 This assumes that the base for the logs is 10. If the base was e then it is likely that "exp" would be used instead of "antilog"
Value of AntiLog (6) is 1,000,000.00
Raise 10 to the power of the number. The antilog of 2 is 102 = 100 The antilog of 5 is 105 = 10,000 The antilog of 'pi' is 103.1416 = 1,385.46 (rounded)
how to find antilog(20/2) answer
It is 1013.309 . If your pocket calculator doesn't do 10x then you use antilog tables. It's a big number. 1013 x antilog of 0.309 might be more handy.
Assuming base-10 logarithms the antilog of 2.068 is 116.95 (to two decimal places).
56
1000
The answer is easy if you are familiar with scientific notation. The antilog of a number, whose integer part is n, has 10n in its scientific notation. Otherwise: the number that you want the antilog for will normally be in decimal form: consisting of an integer part, a decimal point and a fractional part. The number of integer digits in the antilog is one more than the integer part of the number being "antilogged" (exponentiated). antilog(0.1234) = 1.3286*100 = 1.3286 antilog(1.1234) = 1.3286*101 = 13.286 antilog(5.1234) = 1.3286*105 = 132860 antilog(-3.1234) = 1.3286*10-3 = 0.0013286
The value of antilog(1.0913) depends on the base to which the logarithm was taken. Antilog(1.0913) = Base1.0913. The two most common bases are e = 2.71828 (approx) and 10. If the base was e, then antilog(1.0913) = e1.0913 = 2.978 If the base was 10, then antilog(1.0913)= 101.0913 = 12.340
Assuming working to base '10' , then Antilog 2.3909 is 10^(2.3909) = 245.9801149/ Remember for logarithms. log of a number is log(10)[number] Hence its antilog is 10^(log number).
0.008572 (rounded)
1.49968 (rounded)