Oh, dude, it's like you're throwing me back to math class! So, if you have 4 squares, each with sides of 1cm, you just gotta calculate each square's area (1cm x 1cm = 1cm²) and then add them up (4 squares x 1cm² = 4cm²). Boom, there you have it, the total area of those squares is 4 square centimeters.
move
Use squares and try it out for yourself. Get a number of squares and make a rectangle 3 squares long by 4 squares wide. Count the squares. You should have 12 squares (or 3*4). That's the best way I know to prove the formula.
In a 4 by 3 grid, there are a total of 20 squares. To calculate this, you can start by counting the individual squares of each size within the grid. There are 12 one-by-one squares, 6 two-by-two squares, and 2 three-by-three squares. Adding these together gives a total of 20 squares in a 4 by 3 grid.
You would need two 3 cm squares and two 2 cm squares to get a total area of 35 sq cm. A 3 cm square has an area of 9 sq cm and a 2 cm square has an area of 4 sq cm.
Because the 2cm lens has 4 times the area of a 1cm lens. (area = Pi*r2)
4 - without cutting the 1cm x 1cm squares.
Assuming it is 4cm x 4cm, then there would be 16 1cm x 1cm squares. * * * * * But, there are also 9 2cm x 2cm squares, 4 3cm x 3cm squares and 1 4cm x 4cm square. That makes 30 in all.
because it has 16 squares in it so it would have 4 cm for each length i think its 16 tho it is strange that the area and the perimiter are the same...
4 white squares and 4 black squares on each row
There are 12 squares. It can be notes as 4 rows across with 3 squares in each, or as 3 rows down with 4 squares in each.
That depends on the size of the suares. For example, there will be a million squares with sides of 0.001 ft each. If the 12 square ft area is in the form of a 6*2 rectangle, there will be space for 3 squares of 2*2. But if the area is 3*4 then 2*2 squares cannot cover it without overlap.
4 by 4 by4 by4
9 obvious, 3 for each row, 3 for each column, 4 for each rectangle of 4 squares, all of the squares. So 19
To find the area of joined squares, add up the area of each individual square. For instance, I have a square with a side length of 5 attached to another square with a side length of 2 A = 52 + 22 = 25 + 4 = 29 units2
this is stupidinuss
3 squares and 4 triangles will have 24 vertices. There will be 4 vertices for each of the 3 squares. Since there are 3 squares, that will be 12 vertices. There are 3 vertices for each of the 4 triangles. Since there are 4 triangles, that will be 12 vertices. 12+12=24.
To calculate the surface area of a box, find the area of each face, and add all answers together. For example, the surface area of a square whose faces are all 2" by 2" can be calculated with the following equation: 2x2x6 2x2 equals 4. Since a square's sides are all the same length, we can simply multiply 4 by the number of faces on a square(6), instead of 4+4+4+4+4+4. THIS IS ONLY TRUE FOR SQUARES! I REPEAT, THIS IS ONLY TRUE FOR SQUARES!!!! For all other shapes, the sides are NOT all the same length. So THIS IS ONLY TRUE FOR SQUARES!