if you meant to write the problem as "3b + 5 = 29", then this is how to solve: 3b + 5 = 29 - 5 - 5 subtract 5 from each side 3b = 24 simplify b = 8 divide each side by 3 to get b by itself
To simplify the expression 3b^2 - 3b, we first factor out the common factor of 3b. This gives us 3b(b - 1), where b - 1 is the simplified form of the expression. This expression represents the difference between 3 times the square of a variable b and 3 times the variable b.
a = 3b - c a + c = 3b - c + c a + c = 3b (a + c)/3 = 3b/3 ( a + c ) / 3 = b Do your homework.
If b = 5 then 15-10 = 5
a+b+2+3=5+a+b
a = 11 and b = 5.
(2a + b)(a + 3b)
-2
(11, 5)
6
3b2 = 3 divide both sides by 3 b2 = 1 b = 1
(a+b)(3b+1)
12b2 - 8b = 0 4b(3b-2) = 0 4b = 0 and 3b-2 = 0 4b = 0 and 3b = 2 b = 0 and 2/3
-13
3b2 + b - 10 = 0 This quadratic equation can be factored. (3b -5)(b +2) = 0 The equation can be solved when either (3b - 5) = 0, or (b + 2) = 0. If 3b - 5 = 0 then 3b = 5 : b = 5/3 If b + 2 = 0 then b = -2 The roots or solutions to this equation are b = 5/3 and b = -2
if you meant to write the problem as "3b + 5 = 29", then this is how to solve: 3b + 5 = 29 - 5 - 5 subtract 5 from each side 3b = 24 simplify b = 8 divide each side by 3 to get b by itself
If a + b = 6, what is the value of 3a + 3b?