its 0.2 km/min. the formula for speed is S=D/T-S: speed-D: distance-T: time
Use the product and chain rules: d/dt te^(-t²) = (d/dt t)e^(-t²) + t(d/dt e^(-t²)) = 1 × e^(-t²) + t × e^(-t²) × d/dt -t² = e^(-t²) (1 + t × -2t) = (1 - 2t²)e^(-t²)
D = rt t = d/r r = d/t
If the time now is T hours (on a 24 hour clock), then the answer is mod(21 - T, 24) hours.
There are 24 hours in 1 day, so 25 hours = 24 hours + 1 hours = 1 day + 1 hour Thus 25 hours after 09:00 am is 10:00 am on the following day.
Use the formula: V=D/T Where V= Velocity D= Distance T = Time So solving for T T = D / V T = 715miles / 65 Mph T = 11 hours
d=t*v d=3h(90mph) d=270 miles
its 0.2 km/min. the formula for speed is S=D/T-S: speed-D: distance-T: time
If my maths are right, it would take you 45 seconds... S= Speed, D= Distance, T= Time S=D/T T=D/S T=1 / 80 T= 0.0125 hours * 3600 seconds = 45 seconds Czar~
Well, d(istance)=r(ate)*t(ime), so if d=250 miles and r=70 mph, t= 3.6 hours, or 3 hours and 36 minutes.
v = d/t so... t = d/v = 15/12 = 1.25 hours or 1 hr 15 min
4 hours because, D=ST,T=D/S substituting values, T=500/125=4 hrs.
If the car goes from 0 to 25 miles per hour at constant acceleration, the average speed when it reaches 25 mph will be 12.5 mph. Distance (d) traveled during time twhen starting from 0 velocity and accelerating at a constant acceleration of a: d = at²/2 Velocity (v) at time t when starting from velocity 0: v = atso the time it will take to get to 25 mph will be: t = v/a = 25(mph)/aaverage velocity will be: d/t = (at²/2)/t = at/2 = a(25mph/a)/2 = 12.5 mph
Using the formula D/T, you get 29 hours and 22.5 minutes
R=D/T 60 = 230 /T 60T=230 T= 230/60 = 23/6 (23/6) * 60= 230 minutes 3 hours and 50 minutes
These types of questions can be solved with a simple formula, which is actually interchangeable when you need to find distance, speed, and time. T = D/S S = D/T D = S/T So based on the T = D/S formula we get: 278 miles ÷ 70 miles/hr = 3.97 hours
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