35 x 3 = (30 x 3) + (5 x 3) = 90 + 15 = 105
distributive property for (11-3)=
The distributive property is simple. What I do is think of a double rainbow... 5(3+2) = This will be simple. 5 times 3 is fifteen, 5 times 2 is 10. Now that you know about the double rainbow trick, visit math is fun for help with the distributive property.
Which property is illustrated in this problem? (associative, distributive, identity, or commutative) 7d + 3 = 3 + 7d
9(10+3)
3*62 = 3*(60 + 2) which, using the distributive property, is= 3*60 + 3*2 = 180 + 6 = 186.
An expression equal to 15 + 35, using distributive property, is 5(3 + 7). Under distributive property, 5*3=15 and 5*7=35.
To use the distributive property to multiply 3 by 10, you can break down 10 into smaller, more manageable parts. For example, you can express 10 as 5 + 5. Then, apply the distributive property: (3 \times 10 = 3 \times (5 + 5) = (3 \times 5) + (3 \times 5) = 15 + 15 = 30). Thus, 3 times 10 equals 30.
The distributive property states that when you multiply a number by a sum, you can distribute the multiplication across each addend. For example, if you apply this to the expression (12 \times (3 + 5)), it can be rewritten as (12 \times 3 + 12 \times 5). This means that instead of calculating (12 \times 8) directly, you can calculate (36 + 60), which also equals (96).
distributive property for (11-3)=
The distributive property is simple. What I do is think of a double rainbow... 5(3+2) = This will be simple. 5 times 3 is fifteen, 5 times 2 is 10. Now that you know about the double rainbow trick, visit math is fun for help with the distributive property.
8*3.5 = 8*(3 + 0.5) which, applying the distributive property, = 8*3 + 8*0.5 = 24 + 4 = 28
The distributive property states that a product can be broken down into smaller parts. For 90 x 83, you can express 83 as (80 + 3) and then apply the distributive property: (90 \times 83 = 90 \times (80 + 3) = (90 \times 80) + (90 \times 3) = 7200 + 270 = 7470). Thus, 90 x 83 equals 7470.
To rewrite ( 4(f \times 3) ) using the Distributive Property, you can distribute the 4 across the product inside the parentheses. This gives you ( 4f \times 3 ). Therefore, the expression can be rewritten as ( 12f ).
To find the product of 7 and 63 using the distributive property, you can break down 63 into more manageable parts. For example, you can express 63 as 60 + 3. Then, apply the distributive property: (7 \times 63 = 7 \times (60 + 3) = 7 \times 60 + 7 \times 3). This simplifies to (420 + 21), which equals 441.
2(x - 3) = 2x - 6.
The distributive property of multiplication states that for any three numbers, (a), (b), and (c), the equation (a \times (b + c) = (a \times b) + (a \times c)) holds true. This means that when you multiply a number by a sum, you can distribute the multiplication across each addend and then sum the results. It's a fundamental property that simplifies calculations and is widely used in algebra. For example, using the distributive property, (3 \times (4 + 5)) can be calculated as (3 \times 4 + 3 \times 5), resulting in (12 + 15 = 27).
Which property is illustrated in this problem? (associative, distributive, identity, or commutative) 7d + 3 = 3 + 7d