35 x 3 = (30 x 3) + (5 x 3) = 90 + 15 = 105
distributive property for (11-3)=
The distributive property is simple. What I do is think of a double rainbow... 5(3+2) = This will be simple. 5 times 3 is fifteen, 5 times 2 is 10. Now that you know about the double rainbow trick, visit math is fun for help with the distributive property.
Which property is illustrated in this problem? (associative, distributive, identity, or commutative) 7d + 3 = 3 + 7d
9(10+3)
3*62 = 3*(60 + 2) which, using the distributive property, is= 3*60 + 3*2 = 180 + 6 = 186.
An expression equal to 15 + 35, using distributive property, is 5(3 + 7). Under distributive property, 5*3=15 and 5*7=35.
distributive property for (11-3)=
The distributive property is simple. What I do is think of a double rainbow... 5(3+2) = This will be simple. 5 times 3 is fifteen, 5 times 2 is 10. Now that you know about the double rainbow trick, visit math is fun for help with the distributive property.
8*3.5 = 8*(3 + 0.5) which, applying the distributive property, = 8*3 + 8*0.5 = 24 + 4 = 28
To find the product of 7 and 63 using the distributive property, you can break down 63 into more manageable parts. For example, you can express 63 as 60 + 3. Then, apply the distributive property: (7 \times 63 = 7 \times (60 + 3) = 7 \times 60 + 7 \times 3). This simplifies to (420 + 21), which equals 441.
2(x - 3) = 2x - 6.
Which property is illustrated in this problem? (associative, distributive, identity, or commutative) 7d + 3 = 3 + 7d
9(10+3)
(20 x 3) + (2 x 3) = 60 + 6 = 66
3*62 = 3*(60 + 2) which, using the distributive property, is= 3*60 + 3*2 = 180 + 6 = 186.
108
To expand a power, use the distributive property and multiply the base by itself the number of times indicated by the exponent. For example, to expand (x+2)^3, multiply (x+2) by itself three times using the distributive property.