352 is divisible by 1, 2, 4 and 8; not by 3, 5, 6 and 9
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Yes, it is divisible by 2 because it ends with 2, it is also divisible bye 3 because 1+3+2=6. 6 is divisible by 3, therefor 132 is divisible by 3.
Let three consecutive integers be n, n+1 and n+2. If n is divisible by 3 then n+1 and n+2 cannot be divisible by 3 as these numbers will respectively leave remainders of 1 and 2. If n is not divisible by 3 then it will leave a remainder of 1 or 2. If n leaves a remainder of 1, then n+1 leaves a remainder of 2 and n+2 is therefore divisible by 3. If n leaves a remainder of 2, then n+1 is divisible by 3 and n+2 is not divisible by 3 as it leaves a remainder of 1.
Being divisible by 2 and 3: 354 (and 360 if inclusive)Trick:Numbers divisible by 2 always ends with an even number (2,4,6,8,0)So: numbers divisible by 2 strictly between 350 and 360: 352, 354, 356, 358Numbers divisible by 3 have the sum of the digits add up to 3,6,9,12 and so onSince there are only 4 numbers there, just try them one by one352: 3+5+2=10 (not divisible by 3)354: 3+5+4=12 (divisible by 3)356: 3+5+6=14 (not divisible by 3)358: 3+5+8=16 (not divisible by 3)354/2=177354/3=118
between 1 and 600 inclusive there are:300 numbers divisible by 2200 numbers divisible by 3100 numbers divisible by both 2 and 3400 numbers divisible by 2 or 3.
yes. 2 + 1 + 6 = 9 9 is divisible by 3 so 216 is divisible by 3.