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Q: What is 2 3 and 9 divisible by?

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no because to be divisible by 9 the number has to equal 9 for instance 2+9+3+8=22 so it is not divisible by 9. But 32121 3+2+1+2+1=9 so it is divisible by 9

1262 is even, so 1262 is divisible by 2. 1 + 2 + 6 + 2 = 11 which is not divisible by 3 nor 9, so 1262 is not divisible by 3 nor 9.

42 is divisible by 2, 3 and 6 but not by 9.

Because 9 is divisible by 3, this is like the rule where if a number is divisible by 2 and 3 it is also divisible by 6.

Last digit (0) is even, so it is divisible by 2 4 + 3 + 2 + 0 = 9 which is divisible by 3, so it is divisible by 3 last digit is 0 or 5, so it is divisible by 5 4 + 3 + 2 + 0 = 9 which is divisible by 9, so it is divisible by 9 last digit is 0, so it is divisible by 10 → 4320 is divisible by all the numbers 2, 3, 5, 9, 10

Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 2 + 3 + 4 = 9 which is divisible by 3, so 234 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 234 is even so 234 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 234 is divisible by both 2 & 3 so 234 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 2 + 3 + 4 = 9 which is divisible by 9, so 234 is divisible by 9Thus 234 is divisible by all 3, 6 & 9.

It is evenly divisible by 2 and 10 but not by 3 and 9.

It is divisible by 2, 5 and 10, but not 3 and 9.

Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.

To check for divisibility by 9 sum the digits of the number and if this sum is divisible by 9 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 9 so 32643 is divisible by 9. As 9 = 3 × 3, any number divisible by 9 is also divisible by 3, thus as 32643 is divisible by 9 it is also divisible by 3. However, for completeness: to check for divisibility by 3 sum the digits of the number and if this sum is divisible by 3 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 3 so 32643 is divisible by 3.

29,178 is divisible by 2, 3 and 9, not by 5 or 10.

20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.

No, because when something is divisible by 6, it is divisible by 2 or 3. This is divisible by 3, but not 2.

It is divisible by 3.

All numbers divisible by 9 are divisible by 3; since 9 = 3 x 3 all multiples of 9 are also multiples of 3. However, all numbers divisible by 3 are not divisible by 9, eg 6 = 2 x 3 but 6 is not divisible by 9 (since 6 is not a multiple of 9) - it only takes one counter example to disprove a theory.

not divisible by 9.but it is divisible by 4.

1, 2, 7, 3 and 6 are not divisible by 4 and/or 9. 12736 is divisible by 4 but not by 9.

It is divisible by 2, 3, 4, 6 and 9.

It is evenly divisible by 2 and by 3.

No. To find whether the number is divisible by 3, you add each digits and if it's equal to 9 then it's divisible by 3 because 9 is divisible by 3. 9 + 8 + 2 = 19, 1 + 9 = 10... so it's not divisible by 3.

To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 432 is 2 which is one of {2, 4, 6, 8, 0} so 432 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 432: 4 + 3 + 2 = 9 which is one of {3, 6, 9} so 432 is divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 432 is a 2 which is not 0 nor 5, so 432 is not divisible by 5. To be divisible by 6, the number must be divisible by both 2 and 3; these have been tested above and found to be true, so 432 is divisible by 6. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 432: 4 + 3 + 2 = 9 which is 9 so 432 is divisible by 9 To be divisible by 10 the last digit must be a 0; the last digit of 432 is a 2 which is not 0, so 432 is not divisible by 10. 432 is divisible by 2, 3, 6 and 9, but not divisible by 5 nor 10.

54 is divisible by 2. Quotient is 27. 54 is divisible by 3. Quotient is 18. 54 is divisible by 9. Quotient is 6.

29 is not divisible by 9. 29 divided by 9 = 3 and 2/9

yes. 2 + 1 + 6 = 9 9 is divisible by 3 so 216 is divisible by 3.

It is divisible only by 3; It is not divisible by 2, 4, 5, 6, 9, 10. 17211 is odd, so not divisible by 2, 4, 6 nor 10. 1 + 7 + 2 + 1 + 1 = 12 which is divisible by 3, so 17211 is divisible by 3, but 12 is not divisible by 9, so 17211 is not divisible by 9. 17211 does not end in 5 or 0 so not divisible by 5