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What is the sum of 1 and 1?
The sum of 1 and 1 is 2.
What is the sum of the first 25 even numbers?
The sum of the first n positive integers (i.e. 1+2+3+...+n) is given by n(n+1)/2 so the sum of the first 25 positive integers is 1+2+3+...+25 = 25x26/2 = 325. The sum of the first 25 EVEN numbers will be double this i.e. 2+4+6+...+50 = 650.
Sum the integers from 1 to 100?
The sum of the integers from 1 to 100 inclusive is 5,050.
What is the sum of 1 and 8?
The sum of 1 + 8 is 9.
What is an equation to find the sum of all the integers from 1 to 2010?
To calculate the sum of the numbers 1 to n, the formula is: sum = n(1 + n) / 2 So, an equation to find the sum of the integers 1 to 2010 is: sum = 2010 x (1 + 2010) / 2
How do you sum up numbers from 1 to n?
import java.util.Scanner;public class average {static int i=0;static double sum = 0;static double average = 0;public static double calcSum(double sum){double count;Scanner input = new Scanner(System.in);while(i < 5){count = input.nextDouble();sum = sum + count;i++;}return sum;}public static double calcAverage(double average){double sum = calcSum(sum);average = calcSum(sum) / 5;return average;}public static void main(String[] args) {System.out.println("Please enter 5 numbers.");System.out.println("Sum is: "+calcSum(sum));System.out.println("Average is: "+calcAverage(average));}}
Write java program for mean of ten numbers?
// numbers to work with double[] nums = {1, 2, 3, 4.5, 5.5, 6, 7.5, 8, 9, 10}; double sum = 0; // total sum for (int i = 0; i < nums.length; ++i) { sum += nums[i]; } // final average final double mean = (sum / nums.length);
If you add up all of the numbers of a roulette wheel what number would you get?
A roulette wheel has the numbers 1-36 and zero, and sometimes double zero. Zero & double zero sum to 0 The sum of n numbers is 1/2 n(first + last) Sum of numbers of roulette wheel = 1/2 x 36 x (1 + 36) + 0 = 666.
Program to find the sum of harmonic series?
Let's assume that you want the sum of the general harmonic series: sum(n=0,inf): 1/(an+b) Since we know that the harmonic series will converge to infinity, we'll also assume that you want the sum from 0 to n. double genHarmonic(const double n, const double a, const double b) { double sum = 0.0; // perform calculations int k; for(k = 0; k <= n; ++k) { sum += 1.0 / (a * k + b); } return sum; }
Program to find the sum of the series as 1 plus x plus x2 plus x3 plus?
The idea is to use a loop. To reduce the additional effort (and innacuracy) of power calculations, you can do repeated multiplication, as part of the loop. For example, in Java:double sum = 1;double xpower = 1.0;for (int i = 1; i
How do you convert a single sigma sum to a double sigma sum?
Multiply sum by 2.
What is the relationship between the probability of an event and its compliment?
Their sum is 1.Their sum is 1.Their sum is 1.Their sum is 1.
If two fair dice are rolled what is the probability of rolling a double given that the sum was 11?
Let A = rolling a double Let B = sum is 11 P(A)=6/36=1/6 P(B)=2/36=1/18 since (5,6) and (6,5) produce a sum of 11. We want to find P(A/B)= P(A & B) / P(B) = 0 / P(B)=0 P(A & B) represent the event getting a double and the sum being 11.
What is the sum of 1 and 1?
The sum of 1 and 1 is 2.
Math- What does sum mean?
Sum, or summation, is just addition. For example, the sum of 1 and 2 is 1 + 2 = 3. The term "sum" is generally used for large sets or series. For example, the sum of the first 100 natural numbers is 1 + 2 + 3 + ... + 100 = 495. Sum is the total of 2 or more numbers as determined by the math process. Mathematically it means the answer to an addition problem.
How do you Write a java program to find the sum and average of 10 float values?
import java.util.Scanner; public class float_values{ private static double sum = 0, average = 0; public static void main(String[] args){ Scanner reader = new Scanner(System.in); double[] values = new double[10]; for (int count = 0; count < 10; count++){ System.out.println("Enter number " + (count + 1)); values[count] = reader.nextDouble(); } for ( int i = 0; i < values.length; i++){ sum += values[i]; } average = (sum / values.length); System.out.println("The sum of the numbers is " + sum); System.out.println("The average of the numbers is " + average); } }
What is the sum of the first 25 even numbers?
The sum of the first n positive integers (i.e. 1+2+3+...+n) is given by n(n+1)/2 so the sum of the first 25 positive integers is 1+2+3+...+25 = 25x26/2 = 325. The sum of the first 25 EVEN numbers will be double this i.e. 2+4+6+...+50 = 650.
