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a(x + y + z)

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ax + ay +az = a(x + y + z)

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13y ago
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Q: What is factor ax plus ay plus AZ?
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Continue Learning about Other Math

AX plus BY equals AY plus BX what is the general equation?

Assuming the question is about chemical reactions (rather than mathematics where it is placed), it is a double displacement.


A vector A has components Ax 11 m and Ay 43 m What is the the angle that vector A makes with the x-axis?

Theata = Tan^-1(Ay/Ax) Theata = 75.7 deg


One way to find the equation of a line is to look at some points on it and try to find the relationship between the coordinates?

Yes. You need only two points. If A (ax, ay) and B (bx, by) are two points on the line then the gradient (slope) of the line is m = (by - ay)/(bx - ax) provided bx ≠ ax. From this you can calculate m. Then the general slope-intercept form of the equation is y = mx + c Substitute the coordinates of A or B into this equation to find c. If bx = ax then the line is parallel to the y axis and its equation is x = ax. [There are other methods but they are similar to the above]


A vector has components Ax 12 m and Ay 5 m What is the magnitude of vector A?

Sqrt of 122 + 5 2 = 13


AX plus BY equals AY plus BX?

Ax + by = ay + bxax - ay + by - bx = 0a(x - y) + b(x - y) = 0(a + b)(x - y) = 0-----------------------------------------------------Another contributor continued:Great !When I saw this question, I was about to say "No it doesn't. Not unless A=B."But "Blackfireweb" developed a much more in-depth analysis. Unfortunately, there was asmall error in his algebra, in the third line, where he collects like terms from the second line.Repeating Blackfireweb's work:Ax + By = Ay + BxA(x - y) + B(y - x) = 0A(x - y) - B(x - y) = 0(A - B) (x - y) = 0-- The equation can only be true for all (x, y) if ( A = B ).-- Otherwise, it's only true at a point where ( x = y ).What this really means is: Whatever numbers you pick for 'A' and 'B', if you write an equationsuch as appears in the question and then massage it a bit, you always find that you havethe equation ( Y = X ), and you realize that we have all been making something complicatedout of something simple.Notice that the "question" doesn't even ask any question. It just makes a statement.To which we reply: "OK. That's the equation ( Y = X ). So what ?"