Assuming the question is about chemical reactions (rather than mathematics where it is placed), it is a double displacement.
Theata = Tan^-1(Ay/Ax) Theata = 75.7 deg
Yes. You need only two points. If A (ax, ay) and B (bx, by) are two points on the line then the gradient (slope) of the line is m = (by - ay)/(bx - ax) provided bx ≠ ax. From this you can calculate m. Then the general slope-intercept form of the equation is y = mx + c Substitute the coordinates of A or B into this equation to find c. If bx = ax then the line is parallel to the y axis and its equation is x = ax. [There are other methods but they are similar to the above]
Sqrt of 122 + 5 2 = 13
Ax + by = ay + bxax - ay + by - bx = 0a(x - y) + b(x - y) = 0(a + b)(x - y) = 0-----------------------------------------------------Another contributor continued:Great !When I saw this question, I was about to say "No it doesn't. Not unless A=B."But "Blackfireweb" developed a much more in-depth analysis. Unfortunately, there was asmall error in his algebra, in the third line, where he collects like terms from the second line.Repeating Blackfireweb's work:Ax + By = Ay + BxA(x - y) + B(y - x) = 0A(x - y) - B(x - y) = 0(A - B) (x - y) = 0-- The equation can only be true for all (x, y) if ( A = B ).-- Otherwise, it's only true at a point where ( x = y ).What this really means is: Whatever numbers you pick for 'A' and 'B', if you write an equationsuch as appears in the question and then massage it a bit, you always find that you havethe equation ( Y = X ), and you realize that we have all been making something complicatedout of something simple.Notice that the "question" doesn't even ask any question. It just makes a statement.To which we reply: "OK. That's the equation ( Y = X ). So what ?"
ax + ay - AZ = a(x + y - z)
a(x + y - z)
(a - b)(x + y)
A double replacement reaction.
Double Replacement
You can find the magnitude of acceleration by using the formula: magnitude = sqrt(ax^2 + ay^2 + az^2), where ax, ay, and az are the components of acceleration in the x, y, and z directions respectively. Add the squares of the individual components and take the square root of the sum to calculate the magnitude.
Yes. Given A= Iax +J ay +K AZ and B= Ibx + Jby +K bz then, A+B= I(ax + bx) + J(ay + by) + K(AZ + bz).
Recall distributivity a(b + c) = ab + ac = (b + c)a and associativity (ab)c = a(bc) (a + b) + c = a + (b + c) as well as commutativity ab = ba a + b = b + a we are gonna need those. See for yourself when I applied each to learn the trick: ax - bx - ay + yb = (ax - bx) + (-ay + yb) = x(a - b) + -y(a - b) = (x - y)(a - b)
Assuming the question is about chemical reactions (rather than mathematics where it is placed), it is a double displacement.
Your two equations are: AX + BY = A - B BX - AY = A + B + B Because you have four variables (A, B, X, Y), you cannot solve for numerical values for X and Y. There are a total of four answers to this question, solving each equation for X and Y independently. First equation: X = (A - B - BY)/A Y= (A - B - AX)/B Second equation: X = (A +2B +AY)/B Y = (BX - A - 2B)/A
A vector comprises its components, which are orthogonal. If just one of them has magnitude and direction, then the resultant vector has magnitude and direction. Example:- If A is a vector and Ax is zero and Ay is non-zero then, A=Ax+Ay A=0+Ay A=Ay
Theata = Tan^-1(Ay/Ax) Theata = 75.7 deg