5a2 - 20ab - 25b2
= 5(a2 - 4ab - 5b2)
= 5(a2 - 4ba - 5b2) since -5b*b = -5b2 and -5b + b = -4b, then
= 5(a - 5b)(a + b)
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The square root of 25a squared is 5a. The square root of 16 is 4.So the answer is (5a+4)(5a-4)
a2 + -5a2 - a2 - a = a2 - 5a2 - a2 - a = a2 - 6a2 - a = -5a2 - a
30 + ab + 6b + 5a = 5(a+6) + b(a+6) = (b+5)(a+6)
This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a
The GCF is 5a.