a2 + -5a2 - a2 - a = a2 - 5a2 - a2 - a = a2 - 6a2 - a = -5a2 - a
This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a
The square root of 25a squared is 5a. The square root of 16 is 4.So the answer is (5a+4)(5a-4)
2a + 5a + 3a = 10a
5a + 20 = ? Your question is incomplete.
6b+5a-4b+3a= ? Rearrange it as 5a+3a+6b-4b = 8a+2b
No
It simplifies to 5a+4 !
92
The algebraic expression for 5 times a plus 6 times a squared can be written as (5a + 6a^2). In this expression, (5a) represents 5 times the variable (a), and (6a^2) represents 6 times the variable (a) squared.
This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a
Well, honey, 5a squared is just 5 times a squared. It's as simple as that. So if you're looking for the value of 5a squared, just make sure you don't forget to square that 'a' and multiply it by 5. Easy peasy lemon squeezy!
The square root of 25a squared is 5a. The square root of 16 is 4.So the answer is (5a+4)(5a-4)
(a2 + 5a + 6)/(a - 2) = (a + 2)*(a 3)/(a - 2) which cannot be simplified further. It can, however be written as (a2 - 2a + 7a - 14 + 20)/(a - 2) which is (a + 7) + 20/(a - 2)
5a + 3 + (2a - 2) + a= 5a + 3 + 2a - 2 + a= 8a + 1
5a
The GCF of 35 a^2 and 85ab is 5a. The GCF of 35 and 85 is 5, and the GCF of a squared and ab is a.
2a+5a+9a = 16a