0.1111 is greater than 0.11
In any base other than 2 (ie other than binary): 10101010 + 01111 = 10102121 In base 2 (binary): 10101010 + 01111 = 10111001
Yes, .02 > .011
.010
.011
.011
There are an infinite number of values between 0.01 and 0.027 for example .011 .0111 .01111 .01111 .011111 etc. , .012, .0121, .0122, etc.
In any base other than 2 (ie other than binary): 10101010 + 01111 = 10102121 In base 2 (binary): 10101010 + 01111 = 10111001
10101010 + 01111 = 10111001 (170+15 = 185)
Yes, .02 > .011
0.5 is greater than 0.11
011 27662310 011 27662306 Ashish Garg 011 27662310 011 27662306 Ashish Garg 011 27662310 011 27662306 Ashish Garg 011 27662310 011 27662306 Ashish Garg 011 27662310 011 27662306 Ashish Garg
Multiply by 16. ANSWER: The answer is bcd 11 = 3 111 = 7 1111 i= F 01111 =E and so foirth
011 & 009 Since no decimal point is given , then drop the prefix zeroes. Hence 11 & 9 . It follows that 11 > 9
If you mean 011 then it is simply 11.0
3 bit stuffing is required
Base2 011 = 11 Base3 011 = 10 Any base above that: Base2(11) equals 3
tel: 011 560 6000 or 011 560 4724