In any base other than 2 (ie other than binary):
10101010 + 01111 = 10102121
In base 2 (binary):
10101010 + 01111 = 10111001
10,101,010 + 01,111 = 10,102,121Although you didn't say so, we suspect that you may have meantthe two numbers in the question to be binary (base-2) numbers.If so, then| 0 | 0 | 0 | 0= (170)100 | | | | = (15)10Their sum is (185)10
170
Decimal: 170Hex: AA
2 + 8 + 32 + 128 ie 170
Convert each group of 4 bits into one hexadecimal digit. 1010 is "A" in hexadecimal, so this particular number is "AA".
10101010 + 01111 = 10111001 (170+15 = 185)
To find the sum of the binary numbers 10101010 and 01111, first align them for addition: 10101010 + 0010111 ----------- Adding from right to left, we get: 0 + 1 = 1 1 + 1 = 10 (write 0, carry 1) 1 + 1 + 1 (carry) = 11 (write 1, carry 1) 0 + 0 + 1 (carry) = 1 1 + 0 = 1 0 + 0 = 0 1 + 0 = 1 1 + 0 = 1 Combining the results gives us 11010101 in binary. Thus, the sum of 10101010 and 01111 is 11010101.
10,101,010 + 01,111 = 10,102,121Although you didn't say so, we suspect that you may have meantthe two numbers in the question to be binary (base-2) numbers.If so, then| 0 | 0 | 0 | 0= (170)100 | | | | = (15)10Their sum is (185)10
337
10101010 in decimal = 9A2112 in Hex.
10101010 = 10^7 + 10^5 + 10^3 + 10.
101010100
100000100000
10101010
The binary number 10101010 is equivalent, in decimal representation, to 128 + 32 + 8 + 2 = 170. But this answer assumes that the given number is binary - an assumption for which there is no real justification. Besides, the relationship is an equivalence, which is not quite "the same thing".
There are an infinite number of values between 0.01 and 0.027 for example .011 .0111 .01111 .01111 .011111 etc. , .012, .0121, .0122, etc.
170