In any base other than 2 (ie other than binary):
10101010 + 01111 = 10102121
In base 2 (binary):
10101010 + 01111 = 10111001
10,101,010 + 01,111 = 10,102,121Although you didn't say so, we suspect that you may have meantthe two numbers in the question to be binary (base-2) numbers.If so, then| 0 | 0 | 0 | 0= (170)100 | | | | = (15)10Their sum is (185)10
170
Decimal: 170Hex: AA
2 + 8 + 32 + 128 ie 170
Convert each group of 4 bits into one hexadecimal digit. 1010 is "A" in hexadecimal, so this particular number is "AA".
10101010 + 01111 = 10111001 (170+15 = 185)
10,101,010 + 01,111 = 10,102,121Although you didn't say so, we suspect that you may have meantthe two numbers in the question to be binary (base-2) numbers.If so, then| 0 | 0 | 0 | 0= (170)100 | | | | = (15)10Their sum is (185)10
337
10101010 in decimal = 9A2112 in Hex.
10101010 = 10^7 + 10^5 + 10^3 + 10.
101010100
it is 10101010 mggkg
100000100000
10101010
There are an infinite number of values between 0.01 and 0.027 for example .011 .0111 .01111 .01111 .011111 etc. , .012, .0121, .0122, etc.
The binary number 10101010 is equivalent, in decimal representation, to 128 + 32 + 8 + 2 = 170. But this answer assumes that the given number is binary - an assumption for which there is no real justification. Besides, the relationship is an equivalence, which is not quite "the same thing".
170