z = 8/3.
We write y=kx since y varies directly as x. Now we know if x is 5, y is 10. so we write 10=5k so k=2
25
y varies inversely as x2 so y = c/x2 for some constant c. When x = 5, y = 4 So c = x2y = 100 that is y = 100/x2 Then, when x = 2, y = 100/4 = 25
2=8/4 the constant is 8 y-k/x i think.
xy = 8 or y = 8/x
It is 2.
The relationship between w, f, and p can be described as: w = kf/p^2, where k is the constant of proportionality. This means that w is directly proportional to f and inversely proportional to the square of p. If f increases, w will increase, and if p increases, w will decrease.
Since ( x ) varies directly with ( y ) and inversely with ( z ), we can express this relationship as ( x = k \frac{y}{z} ), where ( k ) is a constant. Given that ( x = 5 ) when ( y = 10 ) and ( z = 5 ), we can find ( k ): [ 5 = k \frac{10}{5} \implies k = 2. ] Now, to find ( x ) when ( y = 20 ) and ( z = 10 ): [ x = 2 \frac{20}{10} = 4. ] Thus, ( x ) equals 4.
f(2) = 24.
y is 2/3.
The answer is x=10. If: x=20 y=8 z=4 then: y=8/2=4 z=4*2=8 since x varies directly with y, meaning whatever happens to y, happens to x, so if y was divided by 2, then x should be divided by 2. After all, the inverse of division is multiplication.
x = 24
2
If y varies directly as x and if x = 2 when y = 8 then k = 4.
If y varies directly as x then k = 2.
We write y=kx since y varies directly as x. Now we know if x is 5, y is 10. so we write 10=5k so k=2
25